.欲使滴定时消耗0.10mol•L-1HC1溶液20~25 mL,问应称取基准试剂Na2CO3多少克?此时称量误差能否小 欲使滴定时消耗0.10mol/lhcl溶液2025ml,问应...

\u6b32\u4f7f\u6ef4\u5b9a\u65f6\u6d88\u80170.10mol/LHCI\u6eb6\u6db220-25mL\uff0c\u95ee\u5e94\u53d6\u57fa\u51c6\u8bd5\u5242Na2CO3\u591a\u5c11\u514b\uff1f\u6c42\u6551

0.1X20X106/2X1000\u52300.1X25X106/2X1000
\u53730.106\u514b\u52300.1325\u514b\u4e4b\u95f4

\u6240\u9700Na2CO3\u7684\u6469\u5c14\u8d28\u91cf\uff1a500 ml * 0.1000 mol/l = 0.0500mol Na2CO3\u7684\u6469\u5c14\u8d28\u91cf\uff1a23 * 2 + 12 + 16 *3\uff1d106 g/mol \u6240\u4ee5\u53d60.0500 mol * 106g/mol = 5.3g

你称取碳酸钠0.106g-101325g范围内的任意一个值。
把碳酸钠配成溶液用0.1摩尔每升的盐酸滴定,根据消耗的盐酸量就可以计算称取的碳酸钠的重量。这样就计算出称量误差了。

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    绛旓細鎵闇Na2CO3鐨勬懇灏旇川閲忥細500 ml * 0.1000 mol/l = 0.0500mol Na2CO3鐨勬懇灏旇川閲忥細23 * 2 + 12 + 16 *3锛106 g/mol 鎵浠ュ彇0.0500 mol * 106g/mol = 5.3g
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