欲使滴定时消耗0.1mol/L Hcl溶液20–25ml问应称取基准试剂Na2Co3多少克(Na2 欲使滴定时消耗0.1mol/Lhcl20-25ml 问应称取...
\u6b32\u4f7f\u6ef4\u5b9a\u65f6\u6d88\u80170.10mol/LHCI\u6eb6\u6db220-25mL\uff0c\u95ee\u5e94\u53d6\u57fa\u51c6\u8bd5\u5242Na2CO3\u591a\u5c11\u514b\uff1f\u6c42\u65510.1X20X106/2X1000\u52300.1X25X106/2X1000
\u53730.106\u514b\u52300.1325\u514b\u4e4b\u95f4
0.2g\u5de6\u53f3\u3002
滴定反应：Na2CO3 + 2HCI —— 2NaCI + CO2 + H2O
1 2
m/105.6 0.1*20/1000
m=0.1056g
当V=25时，计算出m=0.132g
要想消耗盐酸的体积在20—25毫升之间，称取碳酸钠的质量范围是0.1056—0.132g。
绛旓細0.1mol/L鐨勬阿姘у寲閽犳憾娑茬殑鏍囧畾鍙0.4-0.6鑼冨洿鍐呮槸涓轰簡浣挎淮瀹鐨勬阿姘у寲閽犳憾娑蹭綋绉湪20-30姣崌涔嬮棿锛岃繖鏍锋爣瀹氱殑娴撳害杈冨噯纭備竴鑸婊村畾鏃锛屾淮瀹氭憾娑茬殑娴撳害鏄0.1 mol/L宸﹀彸锛岃娑堣25mL姘㈡哀鍖栭挔锛屽垯闇瑕佺О閭昏嫰浜岀敳閰告阿閽句负0.5g锛屼负浜嗘帶鍒舵淮瀹氭憾娑茬殑浣撶Н鍦20锛30mL鏃讹紝鍒欓渶瑕侀偦鑻簩鐢查吀姘㈤捑0.4鍒0....
绛旓細2NaOH+H2SO4=Na2SO4+2H2O 娑堣H2SO4鐨勯噺n=0.1*0.02 鍙嶅簲浜2n鐨凬aOH锛2n=c*0.02=2*0.1*0.02 瑙ｅ緱c=0.2mol/L
绛旓細銆愩戜緷鎹涓庣～浠ｇ～閰搁挔鐨婊村畾寮 锛欼2 +2S2O3 2- =2I - +S4O6 2- 銆愩戣绠 纭唬纭吀閰搁挔婊村畾娑插ぇ姒傛鍗囨暟锛歷= CV/c =2x 0.05mol/L 路 25ml/0.1 ml = 25 ml
绛旓細銆愩戝彲浠ラ氳繃鍙嶅簲寮忥紝璁＄畻鍑鸿娴嬪畾鐗╄川鐨勯噺
绛旓細D,寰⒈鎬э紝鍥犱负鏈変竴鍗婄殑纰抽吀閽犲弽搴旂敓鎴愮⒊閰告阿閽狅紝涓ゆ牱閮芥槸鍋忕⒈鎬х殑锛屾晠婧舵恫鍋忕⒈鎬с
绛旓細鐢ㄩ厤缃ソ鐨勭洂閰告憾娑婊村畾鑷崇孩鑹诧紝骞跺湪2鍒嗛挓鍐呬笉鍙樿壊涓虹粓鐐广傦紙涓夛級璁＄畻 N = G /锛圴脳0.053锛夊紡涓細N---鏍囧噯鐩愰吀婧舵恫鐨勫綋閲忔祿搴 G---纰抽吀閽犵殑閲嶉噺锛坓锛塚---鑰楃敤鏍囧噯鐩愰吀婧舵恫鐨勪綋绉 0.053---Na2CO3/2000 涓銆侀厤鍒讹細0.02mol/LHCl婧舵恫锛氶噺鍙1.8姣崌鐩愰吀锛岀紦鎱㈡敞鍏1000ml姘淬0.1mol/LHCl...
绛旓細浣犵О鍙栫⒊閰搁挔0.106g-101325g鑼冨洿鍐呯殑浠绘剰涓涓笺傛妸纰抽吀閽犻厤鎴愭憾娑茬敤0.1鎽╁皵姣忓崌鐨勭洂閰婊村畾锛屾牴鎹娑堣鐨勭洂閰搁噺灏卞彲浠ヨ绠楃О鍙栫殑纰抽吀閽犵殑閲嶉噺銆傝繖鏍峰氨璁＄畻鍑虹О閲忚宸簡銆
绛旓細鐢ㄩ偦鑻簩鐢查吀姘㈤捑(KHC8H4O4)鏍囧畾娴撳害绾︿负0.1mol路L-1NaOH鏃,瑕佹眰鍦婊村畾鏃舵秷鑰NaOH婧舵恫25~30mL,闂簲绉板彇KHC8H4O4澶氬皯鍏?... 鐢ㄩ偦鑻簩鐢查吀姘㈤捑(KHC8H4O4)鏍囧畾娴撳害绾︿负0.1 mol路L-1NaOH鏃,瑕佹眰鍦ㄦ淮瀹氭椂娑堣桸aOH婧舵恫25~30 mL,闂簲绉板彇KHC8H4O4澶氬皯鍏? 灞曞紑 鎴戞潵绛 1...
绛旓細銆愩戜緷鎹涓庣～浠ｇ～閰搁挔婊村畾寮 锛欼2 +2S2O3 2- =2I - +S4O6 2- 銆愩戣绠 纭唬纭吀閰搁挔婊村畾娑叉姣崌鏁帮細v= CV/c =2x 0.05mol/L 路 25ml/0.1 ml = 25 ml
绛旓細閲忓彇40.00ml纰樻憾娑诧紝缃簬纰橀噺鐡涓锛屽姞150ml姘达紝鐢0.1mol/l纭唬纭吀閽犳爣鍑嗘憾娑婊村畾杩戠粓鐐规椂鍔2ml娣绮夋寚绀烘恫锛10g/l锛夛紝缁х画婊村畾鑷虫憾娑茶摑鑹叉秷澶便傚悓鏃跺仛姘娑堣纭唬纭吀閽犵殑绌虹櫧璇曢獙锛氬彇250姣崌姘达紝鍔0.05~0.20姣崌纰樻憾娑插強2ml娣绮夋寚绀烘恫锛10g/l锛夛紝鐢0.1mol/l纭唬纭吀閽犳爣鍑嗘憾娑叉淮瀹氳嚦婧舵恫钃濊壊...
