sinπ.cosπ.sin2π.cos2π分别是多少
sin(\u03c0-\u03b1)-cos(\u03c0+\u03b1)=\u6839\u53f72/4(0<\u03b1<\u03c0),\u6c42sin(\u03c0+\u03b1)+cos(2\u03c0-\u03b1)\u7684\u503c\u56e0\u4e3a\u3000sin\uff08\u03c0\uff0d\u03b1\uff09\uff1dsin\u03b1 \u3000cos\uff08\u03c0\uff0b\u03b1\uff09\uff1d\uff0dcos\u03b1
\u6240\u4ee5\u539f\u5f0f=sin\u03b1+ cos\u03b1=\u6839\u53f7\u4e8c/4
\u5219\uff08sin\u03b1+ cos\u03b1\uff09^2=1/8 \u53731+2sin\u03b1cos\u03b1=1/8
\u6240\u4ee52sin\u03b1cos\u03b1=-7/8 \u7531\u6b64\u5f97\u51fa2/\u03c0<a<\u03c0
sin(a+\u03c0\uff09+cos\uff082\u03c0+a)=\uff0dsin\u03b1+ cos\u03b1 \u5176\u5c0f\u4e8e0
\uff08\uff0dsin\u03b1+ cos\u03b1\uff09^2=1-2sin\u03b1cos\u03b1=1+7/8=15/8
\u6240\u4ee5sin(a+\u03c0\uff09+cos\uff082\u03c0+a)=\uff0dsin\u03b1+ cos\u03b1 = -\u6839\u53f7\u4e0b15/8
cos (\u03c0/6) =cos 30\u5ea6 =(\u6839\u53f73)/2. sin (\u03c0/6) =sin 30\u5ea6 =1/2.\u03c0,\u03c0/2,\u03c0/3,\u03c0/4...\u4e4b\u7c7b\u7684\uff0c\u5316\u4e3a\u89d2\u5ea6\u518d\u6c42\u3002
\u62d3\u5c55\u8d44\u6599\u5728\u76f4\u89d2\u4e09\u89d2\u5f62\u4e2d\uff0c\u2220\u03b1\uff08\u4e0d\u662f\u76f4\u89d2\uff09\u7684\u5bf9\u8fb9\u4e0e\u659c\u8fb9\u7684\u6bd4\u53eb\u505a\u2220\u03b1\u7684\u6b63\u5f26\uff0c\u8bb0\u4f5csin\u03b1\uff0c\u5373sin\u03b1=\u2220\u03b1\u7684\u5bf9\u8fb9/\u2220\u03b1\u7684\u659c\u8fb9 \u3002sin\u03b1\u5728\u62c9\u4e01\u6587\u4e2d\u8ba1\u505asinus\u3002
\u5728\u53e4\u4ee3\u7684\u8bf4\u6cd5\u5f53\u4e2d\uff0c\u6b63\u5f26\u662f\u52fe\u4e0e\u5f26\u7684\u6bd4\u4f8b\u3002 \u53e4\u4ee3\u8bf4\u7684\u201c\u52fe\u4e09\u80a1\u56db\u5f26\u4e94\u201d\u4e2d\u7684\u201c\u5f26\u201d\uff0c\u5c31\u662f\u76f4\u89d2\u4e09\u89d2\u5f62\u4e2d\u7684\u659c\u8fb9\u3002 \u80a1\u5c31\u662f\u4eba\u7684\u5927\u817f\uff0c\u53e4\u4eba\u79f0\u76f4\u89d2\u4e09\u89d2\u5f62\u4e2d\u957f\u7684\u90a3\u4e2a\u76f4\u89d2\u8fb9\u4e3a\u201c\u80a1\u201d\u3002
\u53c2\u8003\u8d44\u6599\uff1asin-\u767e\u5ea6\u767e\u79d1
cosπ=-1
sin2π=0
cos2π=1
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绛旓細sin0=0 sin蟺/6=0.5 sin蟺/4=0.7071=浜屽垎涔嬫牴鍙2 sin蟺/3=0.8660=浜屽垎涔嬫牴鍙3 sin蟺/2=1 cos0=1 cos蟺/6=0.866025404=浜屽垎涔嬫牴鍙3 cos蟺/40.707106781=浜屽垎涔嬫牴鍙2 cos蟺/3=0.5 cos蟺/2=0 tan0=0 tan蟺/6=0.577350269=涓夊垎涔嬫牴鍙3 tan蟺/4=1 tan蟺/3=1.732050808=...
绛旓細cos蟺11cos2蟺11cos3蟺11cos4蟺11cos5蟺11=2sin蟺11cos蟺11cos2蟺11cos3蟺11cos4蟺11cos5蟺112sin蟺11=sin2蟺11cos2蟺11cos3蟺11cos4蟺11cos5蟺112sin蟺11=12sin4蟺11cos3蟺11cos4蟺11cos5蟺112sin蟺11=14sin8蟺11cos3蟺11cos5蟺112sin蟺11=14sin(蟺?3蟺11)cos3蟺11cos5蟺112...
