求y=sinx的绝对值在x=0处的连续性和可导性,急求!!! 讨论f(x)=sinx在x=0处的连续性和可导性

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\u8981\u5728x=0\u5904\u8fde\u7eed,\u90a3\u4e48\u51fd\u6570\u57280\u5904\u7684\u5de6\u53f3\u6781\u9650\u8981\u90fd\u5b58\u5728\u5e76\u4e14\u548c\u8be5\u70b9\u7684\u51fd\u6570\u503c\u76f8\u7b49;\u800c\u53ef\u5bfc\u6027\u662f\u5efa\u7acb\u5728\u8fde\u7eed\u7684\u57fa\u7840\u4e0a\u7684\uff08\u53ef\u5bfc\u5fc5\u8fde\u7eed\uff09\uff0c\u8981\u6c42\u51fd\u6570\u5728x=0\u5904\u5de6\u53f3\u5bfc\u6570\u5747\u76f8\u7b49\u3002\u539f\u51fd\u6570\u53ef\u8868\u8fbe\u4e3ay=-sinx\uff08-\u03c0<x<0\uff09\uff0cy=sinx\uff080\u2264x<\u03c0\uff09\u3002\u5f53x\u21920-\u65f6\uff0c\u6709y=-sinx\u21920\uff1b\u5f53x\u21920+\u65f6\uff0c\u6709y=sinx\u21920\uff1b\u5f53x=0\u65f6\uff0c\u6709y=sin0=0\uff0c\u56e0\u4e3a\u5728x=0\u5904\u7684\u5de6\u53f3\u6781\u9650\u5b58\u5728\u4e14\u4e0e\u8be5\u70b9\u7684\u51fd\u6570\u503c\u76f8\u7b49\uff0c\u6240\u4ee5\u51fd\u6570\u5728x=0\u5904\u8fde\u7eed\u3002y'(x\u21920-\uff09=-cosx=-1\uff0cy'(x\u21920+\uff09=cosx=1\uff0c\u663e\u7136y'(x\u21920+\uff09\u2260y'(x\u21920-\uff09\uff0c\u56e0\u800c\u51fd\u6570\u5728x=0\u5904\u4e0d\u53ef\u5bfc\u3002

\u89e3\uff1a
x\u21920\uff0b
lim\uff5csinx\uff5c\uff1dlimsinx\uff1d0\uff1dsin0
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\u5de6\u53f3\u90fd\u8fde\u7eed\uff0e\u6240\u4ee5\u8fde\u7eed
x\u21920\uff0b
lim\uff08\uff5csinx\uff5c\uff0d\uff5csin0\uff09\uff5c\uff0f\uff08x\uff0d0\uff09\uff1dlimsinx\uff0fx\uff1d1
x\u21920\uff0d
lim\uff08\uff5csinx\uff5c\uff0d\uff5csin0\uff09\uff5c\uff0f\uff08x\uff0d0\uff09\uff1dlim\uff0dsinx\uff0fx\uff1d\uff0d1
\u5de6\u53f3\u5bfc\u6570\u4e0d\u7b49\uff0c\u6240\u4ee5\u4e0d\u53ef\u5bfc\u3002

\u8fde\u7eed\u6027\uff1ay\u5728X\u7684\u9886\u57df\u5185\u5904\u6709\u5b9a\u4e49\uff0c\u800c\u4e14y\u5728X\u8d8b\u5411\u4e8e0\u65f6\u6781\u9650\u5b58\u5728\uff0c\u800c\u4e14\u6781\u9650\u503c\u7b49\u4e8ey\u5728X\uff1d0\u7684\u503c\u3002\u8bc1\u660e\u6781\u9650\u5b58\u5728\uff0c\u8981\u770b\u5de6\u53f3\u6781\u9650\u662f\u5426\u5b58\u5728\u4e14\u76f8\u7b49\uff0c\u50cf\u8fd9\u51fd\u6570\uff0c\u5de6\u53f3\u6781\u9650\u90fd\u5b58\u5728\uff0c\u4e14\u90fd\u7b49\u4e8e0\uff0c\u800c\u4e14\u6781\u9650\u503c\u7b49\u4e8e\u51fd\u6570\u503c\u3002
\u53ef\u5bfc\u6027\uff1a\u5148\u5bf9\u51fd\u6570\u8fdb\u884c\u6c42\u5bfc\uff0c\u518d\u6c42\u5176\u5728X\uff1d0\u5904\u5de6\u53f3\u6781\u9650\u662f\u5426\u5b58\u5728\u4e14\u76f8\u7b49\uff0c\u5982\u679c\u4e0d\u5b58\u5728\uff0c\u5219\u4e0d\u53ef\u5bfc\uff0c\u5982\u679c\u5b58\u5728\u53ef\u662f\u4e0d\u76f8\u7b49\uff0c\u4e5f\u4e0d\u53ef\u5bfc\u3002

\u6269\u5c55\u8d44\u6599
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\u5219\u4e3a\u5728\uff08a\uff0cb\uff09\u8fde\u7eed\uff0c\u82e5\u53c8\u5728a\u70b9\u53f3\u8fde\u7eed\uff0cb\u70b9\u5de6\u8fde\u7eed\uff0c\u5219\u5728\u95ed\u533a\u95f4\uff3ba\uff0cb\uff3d\u8fde\u7eed\uff0c\u5982\u679c\u5728\u6574\u4e2a\u5b9a\u4e49\u57df\u5185\u8fde\u7eed\uff0c\u5219\u79f0\u4e3a\u8fde\u7eed\u51fd\u6570\u3002
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y'(0-)= lim(x→0-) (|sinx|-|sin0|)/(x-0)= lim(x→0-) (-sinx-sin0)/(x-0)=-[sin(x+0)/2*cos(x-0)/2]/(x-0)=-1。
y'(0+)= lim(x→0+) (sinx-sin0)/(x-0)=1。左右导数不相等。所以不可导。

lim(x→0-)|sinx|=lim(x→0+)|sinx|=|sin(0)|
∴y在x=0处连续;
∵y=sinx 0≤x≤π
y=-sinx π≤x≤0
∴y'(0-)=-cos(0)=-1
y'(0+)=cos(0)=+1
∴y在x=0处不可导。



连续可导
y'(0-)= lim(x→0-) (sinx-sin0)/(x-0)=1
y'(0+)= lim(x→0+) (sinx-sin0)/(x-0)=1=y'(0-)

y=|x|在x=0处是不可导的,不能这样用夹逼定理。

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