3阶行列式的展开式 三阶行列式的展开式是怎么计算的?n阶的呢?

\u4e09\u9636\u884c\u5217\u5f0f(3\u9636\u77e9\u9635)\u7684\u5c55\u5f00\u5f0f\u5b50

\u66f2\u9762\u4e0a\u4efb\u4e00\u70b9(x,y,z)\u6ee1\u8db3x^2+y^2+z^2=R^2\uff0c\u56e0\u6b64\u88ab\u79ef\u51fd\u6570x^2+y^2+z^2=R^2\uff0c
\u8fdb\u800c\uff1a\u222b\u222bx^2+y^2+z^2ds = \u222b\u222bR^2ds = R^2*\u222b\u222bds = R^2 * 4\u03c0R^2 = 4\u03c0R^4
\u5176\u4e2d\u222b\u222bds\u8868\u793a\u7403\u9762x^2+y^2+z^2=R^2\u7684\u8868\u9762\u79ef\u53734\u03c0R^2

\u54c8\u2026\u6211\u521a\u597d\u5728\u590d\u4e60\u3002\u4e0d\u8fc7\uff0c\u8be5\u600e\u4e48\u8bf4\u5462\uff1f\u90a3\u4e2a\u2026\u4f60\u77e5\u9053n\u9636\u884c\u5217\u5f0f\u7684\u7ed3\u6784\u5417\uff1f\u5b83\u7684\u503c\u7b49\u4e8e\u6240\u6709\u53d6\u81ea\u4e0d\u540c\u884c\u4e0d\u540c\u5217\u7684n\u4e2a\u5143\u7d20\u7684\u4e58\u79ef\u7684\u4ee3\u6570\u548c\u3002\u800c\u6bcf\u4e00\u9879\u4e58\u79ef\u7684\u6b63\u8d1f\u53d6\u51b3\u4e8e\u5b83\u662f\u5076\u6392\u5217\uff08\u4e3a\u6b63\uff09\u8fd8\u662f\u5947\u6392\u5217\uff08\u4e3a\u8d1f\uff09\u2026\u81f3\u4e8e\u6392\u5217\u2026\u5443\uff0c\u4f60\u77e5\u9053\u5417\uff1f\u5509\u2026\u6211\u90fd\u4e0d\u77e5\u9053\u5728\u624b\u673a\u4e0a\u8be5\u600e\u4e48\u8868\u8fbe\u2026\u5982\u679c\u662f\u4e09\u9636\u884c\u5217\u5f0f\uff08\u4e0b\u6807\u6807\u5f97\u89c4\u8303\u7684\u8bdd\uff09\uff0c\u7b49\u4e8ea11a22a33\uff0ba12a23a31\uff0ba13a21a32\uff0da13a22a31\uff0da12a21a33\uff0da11a23a32. \u545c\u545c\u545c\u2026\u6211\u5feb\u8981\u54ed\u4e86\uff01\u987a\u4fbf\u8bf4\u4e00\u4e0b\uff1a\u201c\u6211\u662f\u5b66\u6570\u5b66\u7684\uff01\u201d\u6211\u89c9\u5f97\u4f60\u8fd8\u662f\u627e\u672c\u4e66\u5427\uff5e

三阶行列式展开如下所示:





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