y=1+sin的平方x如何化一 y=sin平方x-1/2怎么化成y=Asin（ax+b)或者...
y\uff1dsin\u5e73\u65b9x\uff0bcos\u5e73\u65b9x\u4e0ey\uff1d1\u662f\u5426\u4e3a\u540c\u4e00\u51fd\u6570\u662f\u7684
y=sin\u5e73\u65b9x-1/2=1/2\uff08cos2x-1)-1/2=1/2cos2x-1
sin²x=（1-cos2x）/2∴原式=1+（1-cos2x）/2
=（3-cos2x）/2
绛旓細sin²x=锛1-cos2x锛/2 鈭村師寮=1+锛1-cos2x锛/2 =锛3-cos2x锛/2
绛旓細绗竴姝ワ細(sinz)^2=1/2-(sin2z)/2 绗簩姝ワ紙璇炬湰涓凡缁欏嚭锛夛細sinx=sina+(sina)'(x-a)/1+(sina)''(x-a)^2/2!+鈥︹﹀皢a=0浠ｅ叆鍚庡緱鍒帮細sinx=x+(-1)x^3/3!+x^5/5!+鈥︹=鈭(-1)^nx^(2n+1)/(2n+1)锛佲︹(鍏朵腑鈭戜笅闄恘=0涓婇檺涓+鈭)绗笁姝ワ細涓婂紡x鎹负2z锛屼唬鍏ョ涓...
绛旓細sin骞虫柟x鐨勫鏁板彲浠ュ啓鎴愶細锛坰in²x锛'=2sinx锛坰inx锛'=2sinxcosx=sin2x銆sinx骞虫柟锛y=sinx^2锛寉'=cosx^2*2x=2xcosx^2 瀵兼暟鏄嚱鏁板浘鍍忓湪鏌愪竴鐐瑰鐨勬枩鐜囷紝涔熷氨鏄旱鍧愭爣澧為噺锛埼攜锛夊拰妯潗鏍囧閲忥紙螖x锛夊湪螖x-->0鏃剁殑姣斿笺傚井鍒嗘槸鎸囧嚱鏁板浘鍍忓湪鏌愪竴鐐瑰鐨勫垏绾垮湪妯潗鏍囧彇寰楀閲徫攛浠ュ悗锛...
绛旓細鏄俧(x)=1涓巊(x)=sin骞虫柟x+cos骞虫柟x鏄浉鍚岀殑鍑芥暟鍥犱负瀹冧滑鐨勫畾涔夊煙鐩稿悓锛屽煎煙涔熺浉鍚岋紝鎵浠ユ槸銆y=sin²x+cos²x锛屾湁瀛︾敓浼氳涓鸿繖鏄嚱鏁帮紝鍥犱负闀垮緱瀹炲湪澶薄鍑芥暟浜嗐傞泦A涓殑浠讳綍涓涓暟x锛屽湪闆咮涓兘鏈夊敮涓鐨勬暟y涓庝箣瀵瑰簲"锛岀劧鍚庣粰鍑芥暟娲诲姩鍒跺畾浜嗕竴涓邯寰嬭鍒欙紝绉板搴旀硶鍒檉涓洪泦A鍒伴泦...
绛旓細sin²伪+cos²伪=1 sin鐨勫钩鏂銆乧os鐨勫钩鏂广 tan鐨勫钩鏂 鐨勫叕寮忔槸锛1銆乻in²伪+cos²伪=1 2銆1+tan²伪=sec²伪 3銆1+cot²伪=csc²伪 4銆乻in²伪=(1-cos2a)/2 5銆乧os²a=(1+cos2a)/2 6銆乼an²a=(2tana-1)/(tan2a...
绛旓細y=sin²x=(1-cos(2x))/2 鎵浠ユ槸瀵圭О娉㈠舰銆
绛旓細瀵兼暟涓嶄竴鏍凤細y=sin^2x--y'=2sinxcosx=sin2x y=sinx^2--y'=cosx^2*2x=2xcosx^2 鍏朵粬瀵兼暟鍏紡锛1銆亂=c(c涓哄父鏁) y'=0 2銆y=x^n y'=nx^(n-1)3銆亂=a^x y'=a^xlna 4銆亂=e^x y'=e^x 5銆亂=logax y'=logae/x 6銆亂=lnx y'=1/x 7銆亂=sinx y'=cosx 8銆亂=...
绛旓細杩愮畻鏂规硶鏈変互涓嬩袱绉嶏細1.(sin²x)' = 2sinx(sinx)' = 2sinxcosx = sin2x銆2.(sin²x)' = [(1-cos2x)/2]' = [1/2 - (cos2x)/2]' = 0 - ½(-sin2x)(2x)' = ½(sin2x)脳2 = sin2x銆
绛旓細鏂圭▼ sin²x=1-cos²x 鏄瘯杈惧摜鎷夋柉鎭掔瓑寮忋傚畠鎸囧嚭锛屼竴涓搴︾殑姝ｅ鸡骞虫柟绛変簬 1 鍑忓幓鍚屼竴涓搴︾殑浣欏鸡骞虫柟銆傝繖涓亽绛夊紡鍙互浠庡嬀鑲″畾鐞嗗鍑猴紝璇ュ畾鐞嗘寚鍑猴紝鍦ㄧ洿瑙掍笁瑙掑舰涓紝鏂滆竟鐨勫钩鏂绛変簬鍏朵粬涓ゆ潯杈圭殑骞虫柟鍜屻傚浜庢寮﹀拰浣欏鸡鍑芥暟锛屾枩杈规槸鍗曚綅鍦嗙殑鍗婂緞锛屽彟澶栦袱鏉¤竟鍒嗗埆鏄崟浣嶅渾涓婁竴鐐圭殑 x ...
绛旓細y=1/2sin2x T=2蟺/2=蟺 鎵浠=-蟺/2,y=1/2sin(-蟺)=0 x=-蟺/4,y=1/2sin(-蟺/2)=-1/2 x=0,y=1/2sin0=0 x=蟺/4,y=1/2sin(蟺/2)=1/2 x=蟺/2,y=1/2sin蟺=0 y=sinxcosx=1/2sin2x 鍜屼笂闈竴鏍 y=2sinx/2 T=2蟺/(1/2)=4蟺 鎵浠 x=-2蟺,y=2sin...
