等价无穷小的证明 高数中的等价无穷小要怎么证明

\u8fd9\u4e2a\u7b49\u4ef7\u65e0\u7a77\u5c0f\u5982\u4f55\u8bc1\u660e

\u719f\u8bb0\u5e38\u7528\u7b49\u4ef7\u65e0\u7a77\u5c0f\u91cf\u53ca\u5176\u548c\u5dee\u3002

\u4e00\u822c\u60c5\u5f62\uff0c\u4f7f\u7528\u6d1b\u5fc5\u8fbe\uff08L\\'Hospital\uff09\u6cd5\u5219\uff0c\u6216\u8005Taylor\u516c\u5f0f\u3002

\u4e3e\u4f8b\uff1ax\u21920\u65f6\uff0csinx\uff0dx\u7684\u7b49\u4ef7\u65e0\u7a77\u5c0f\u91cf\uff1f

\u65b9\u6cd5\u4e00\uff1a\u8bbex\u21920\u65f6\uff0csinx\uff0dx\uff5eAx^k\u3002A\uff0ck\u5f85\u5b9a\u3002\u7531\u6d1b\u5fc5\u8fbe\u6cd5\u5219\uff0c

x\u21920\u65f6\uff0clim\uff08sinx\uff0dx\uff09/Ax^k\uff1dlim\uff08cosx\uff0d1\uff09/Akx^(k\uff0d1)\uff0c\u5206\u5b50\u66ff\u6362\u4e3a\u7b49\u4ef7\u65e0\u7a77\u5c0f\u91cf\uff0d1/2\u00d7x^2\u3002\u5f97
x\u21920\u65f6\uff0clim\uff08sinx\uff0dx\uff09/Ax^k\uff1d\uff0d1/2Ak\u00d7lim x^(3\uff0dk)\u3002
\u7531\u6b64\u6781\u9650\u7b49\u4e8e1\uff0c\u5f97k\uff1d3\uff0c\uff0d1/2Ak\uff1d1\uff0cA\uff1d\uff0d1/6\u3002

\u6240\u4ee5\uff0cx\u21920\u65f6\uff0csinx\uff0dx\uff5e\uff0d1/6\u00d7x^3\u3002

\u65b9\u6cd5\u4e8c\uff1a
sinx\u5728x\uff1d0\u5904\u7684Taylor\u516c\u5f0f\u662fsinx\uff1dx\uff0d1/3!\u00d7x^3\uff0b1/5!\u00d7x^5+...\uff0c\u6240\u4ee5sinx\uff0dx\uff1d\uff0d1/6\u00d7x^3\uff0d1/120\u00d7x^5+...\uff1d\uff0d1/6\u00d7x^3(1+1/20\u00d7x^2+...)\u3002
x\u21920\u65f6\uff0c\u62ec\u53f7\u5185\u7684\u51fd\u6570\u8d8b\u5411\u4e8e1\uff0c\u6240\u4ee5
x\u21920\u65f6\uff0csinx\uff0dx\uff5e\uff0d1/6\u00d7x^3\u3002

\u6d1b\u5fc5\u8fbe\u6cd5\u5219\uff0c[ln(1+x)]'=1/(x+1) [e^x-1]'=e^x \u5206\u6bcd\u5bfc\u6570\u90fd\u662f1\uff0c\u90a3\u4e0d\u5c31\u5206\u522b\u53d8\u6210\u4e861/(1+x)\u548ce^x\u5f53x\u21920\u65f6\u7684\u6781\u9650\u3002
lim(x->0) ( 1- cosx) /(x^2/2)
=lim(x->0) 2( 1- cosx) / x^2 (0/0 \u5206\u5b50\u5206\u6bcd\u5206\u522b\u6c42\u5bfc)
=lim(x->0) 2sinx/(2x)
=1
1- cosx ~ x^2/2

\u65e0\u7a77\u5c0f\u7684\u6027\u8d28\uff1a
1\u3001\u6709\u9650\u4e2a\u65e0\u7a77\u5c0f\u91cf\u4e4b\u548c\u4ecd\u662f\u65e0\u7a77\u5c0f\u91cf\u3002
2\u3001\u6709\u9650\u4e2a\u65e0\u7a77\u5c0f\u91cf\u4e4b\u79ef\u4ecd\u662f\u65e0\u7a77\u5c0f\u91cf\u3002
3\u3001\u6709\u754c\u51fd\u6570\u4e0e\u65e0\u7a77\u5c0f\u91cf\u4e4b\u79ef\u4e3a\u65e0\u7a77\u5c0f\u91cf\u3002
4\u3001\u7279\u522b\u5730\uff0c\u5e38\u6570\u548c\u65e0\u7a77\u5c0f\u91cf\u7684\u4e58\u79ef\u4e5f\u4e3a\u65e0\u7a77\u5c0f\u91cf\u3002
5\u3001\u6052\u4e0d\u4e3a\u96f6\u7684\u65e0\u7a77\u5c0f\u91cf\u7684\u5012\u6570\u4e3a\u65e0\u7a77\u5927\uff0c\u65e0\u7a77\u5927\u7684\u5012\u6570\u4e3a\u65e0\u7a77\u5c0f\u3002

本题是按照等价无穷小量的定义来做。步骤:1.作比并取极限;2.分子有理化;3.约去分子分母中的x;4.求极限;5.根据定义下结论。

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