matlab求解矩阵方程,兄弟们帮帮小弟吧

matlab \u89e3\u77e9\u9635\u65b9\u7a0b

\u8fd9\u4e2a\u95ee\u9898\u4ffa\u4e5f\u611f\u5174\u8da3\uff0c\u63d0\u4f9b\u4e00\u79cd\u65b9\u6cd5\uff0c\u4ec5\u4f9b\u53c2\u8003\u3002

clc;clear
P=sym('[p11 p12 p13;p21 p22 p23;p31 p32 p33]')
A=rand(3,3)
At=A'
Q=diag(diag(A))
f=At*P+P*A+Q

\u7ed3\u679c\uff1a

P =

[ p11, p12, p13]
[ p21, p22, p23]
[ p31, p32, p33]



A =

0.3311 0.5676 0.1526
0.6586 0.9805 0.8330
0.8636 0.7918 0.1919


At =

0.3311 0.6586 0.8636
0.5676 0.9805 0.7918
0.1526 0.8330 0.1919


Q =

0.3311 0 0
0 0.9805 0
0 0 0.1919


f =

[ .6622*p11+.6586*p21+.8636*p31+.6586*p12+.8636*p13+.3311, 1.312*p12+.6586*p22+.8636*p32+.5676*p11+.7918*p13, .5230*p13+.6586*p23+.8636*p33+.1526*p11+.8330*p12]
[ .5676*p11+1.312*p21+.7918*p31+.6586*p22+.8636*p23, .5676*p12+1.961*p22+.7918*p32+.5676*p21+.7918*p23+.9805, .5676*p13+1.172*p23+.7918*p33+.1526*p21+.8330*p22]
[ .1526*p11+.8330*p21+.5230*p31+.6586*p32+.8636*p33, .1526*p12+.8330*p22+1.172*p32+.5676*p31+.7918*p33, .1526*p13+.8330*p23+.3837*p33+.1526*p31+.8330*p32+.1919]

\u7136\u540e\u7528solve\u89e39\u4e2a\u65b9\u7a0b\u7ec4\uff0c\u6c42\u5f97P\uff0c\u4e0d\u8fc7\uff0c\u4ffa\u89c9\u7740\uff0c\u8fd9\u65b9\u6cd5\u592a\u7b28\u3002

X=b\u4e58\u4ee5A\u7684\u9006\uff0cA\u7684\u9006\u53ef\u4ee5\u7528inv(A)\u89e3\u51fa

秩 rank(A)
行列式 det(A)
迹 trace(A)
逆 inv(A)
行最简形矩阵 rref(A)
特征值和特征向量 [d,v] = eig(A)
解矩阵方程 AX=B A\B

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