取0.10mol/LH3PO4 200mL和0.10mol/LNaOH多少mL可以配制pH=7.2 用0.02mol/lH3PO4溶液和0.02mol/lNAO...
\u53d60.1mol/LH3po4 200mol\u548c0.1mol/LNaOH\u591a\u5c11ml\u53ef\u4ee5\u914d\u5236PH=7.2pH=7.21\uff0c\u6eb6\u6db2\u4e3aH2PO4-\u4e0eHPO42-\u7684\u7f13\u51b2\u6eb6\u6db2
\u75280.02mol/lH3PO4\u6eb6\u6db2\u548c0.02mol/lNAOH\u6eb6\u6db2\u914d\u5236100mlPH=7.40\u7684\u751f\u7406\u7f13\u51b2\u6eb6\u6db2\uff0c\u6c42\u9700H3P
\u8fd1\u4f3c\u516c\u5f0f\uff1apH=pKa+lg\uff08cA/cHA\uff09,\u5728\u7b2c\u4e00\u4e2a\u95ee\u9898\u4e2d\u4f60\u9700\u8981\u627e\u51fa\u5171\u8f6d\u9178\u78b1\u5bf9,\u628aKH2PO4\u770b\u6210\u662f\u9178HA,Na2HPO4\u5c31\u662f\u5b83\u7684\u5171\u8f6d\u78b1A-,\u6240\u4ee5\u9009pKa2=7.21,\u4ee3\u5165\u53ef\u5f97lg\uff08cA/cHA\uff09=0.19,\u8fdb\u4e00\u6b65\u5f97\u5230\uff08cA/cHA\uff09=1.549,\u7531\u4e8e\u539f\u6d53\u5ea6\u76f8\u540c,\u6b64\u6bd4\u4e3a\u53d6\u7528\u7684\u4f53\u79ef\u6bd4,\u53ef\u5f97\u7ed3\u679c\u4e3a60.78ml\u548c39.22ml
\u7b2c\u4e8c\u9898\u53ef\u770b\u6210\u53cd\u5e94\u540eHAc\u548cNaAc\u5404\u4e00\u534a,\u5373\u6d53\u5ea6\u76f8\u7b49,\u5219\u6709pH=pKa+lg1= pKa=4.74
\u7b2c\u4e09\u9898\uff08\u52a0\u5165\u76d0\u9178\u5219Tris.HCl\u589e\u591a,\u800cTris\u51cf\u5c11\uff09\u8bbe\u52a0\u5165xmL\u76d0\u9178,\u5373\u6709
7.40=7.85+lg\uff080.05\u00d7100-0.05x\uff09/(0.05\u00d7100+0.05x)
\u4f46x=44\u5de6\u53f3
2H3PO4+3NaOH=NaH2PO4+Na2HPO4+3H2O
2-------------3---------1------------1
0.02---------0.03------0.02---------0.02
需要0.10mol/L氢氧化钠溶液的体积为1000*0.03/0.1=300ml.
绛旓細NaOH鐨勬爣瀹氭槸涔熸槸鍒╃敤閰哥⒈婊村畾鐨勫師鐞嗐傞氬父鍒╃敤鍒嗘瀽澶╁钩鍑嗙‘绉伴噺锛堜竴鑸簿纭埌灏忔暟鐐瑰悗4浣嶏級涓瀹氶噺鐨勫熀鍑嗙墿锛堝鑽夐吀鎴栭偦鑻簩鐢查吀姘㈤捑锛夛紝婧朵簬灏戦噺鐨勬按涓紝鐒跺悗鐢∟aOH婊村畾锛屾牴鎹秷鑰楃殑NaOH浣撶Н璁＄畻鍑哄叾鍑嗙‘娴撳害锛岃娴撳害涓鑸篃鏄簿纭埌灏忔暟鐐瑰悗4浣嶏紙濡0.1025 mol/L锛夈侼aOH娴撳害纭畾涓嬫潵浠ュ悗锛屽氨鍙互浠ユ涓...
绛旓細娑堣楃殑AgNO3鐗╄川鐨勯噺=0.1000*44.20*10锛-3锛=4.420*10锛-3锛夈傚垯姘瀛愮殑鐗╄川鐨勯噺=閾剁瀛愮殑鐗╄川鐨勯噺=4.420*10锛-3锛夈傛按婧舵ф隘鍖栫墿鏈夋隘鍖栭捑銆佹隘鍖栭挔銆佹隘鍖栭晛绛夌瓑锛岄涓苟鏈槑纭寚鍑猴紝鍥犱负鏃犳硶瑙ｇ瓟銆傚彧鑳界畻鍑烘牱鍝佷腑姘瀛愮殑鍚噺銆
绛旓細鏃犳按纰抽吀閽犲拰鐩愰吀鐨勫弽搴斿紡濡備笅锛歂a2CO3+HCI==2NaCI+CO2+H20 璁綱琛ㄧず鐢ㄥ幓鐩愰吀鐨勪綋绉紙ml)锛孋琛ㄧず鏃犳按纰抽吀閽犵殑娴撳害锛坈om/L锛塵琛ㄧず绉板彇鏃犳按纰抽吀閽犵殑璐ㄩ噺锛堝厠)锛屽垯鏈変笅鍒楀叧绯伙細C*V=m*1000/53.00 (53.00鏄1/2Na2CO3鐨勬懇灏旇川閲忥級璁＄畻鍚庢棤姘寸⒊閰搁挔鐨勭О鏍疯寖鍥存槸锛0.106鈥0.1325锛堝厠锛夊噺閲...
绛旓細鎽╁皵鐩愬寲瀛﹀紡(NH4)2Fe(SO4)2.6H2O锛屽弽搴斿氨鎸塊MnO4+5Fe锛圛I锛=Mn锛圛I锛+5Fe锛圛II锛夌畻灏卞ソ浜
绛旓細娴撶～閰哥█閲婂墠鍚庢憾璐ㄧ殑鐗╄川鐨勯噺涓嶅彉锛岃娴撶～閰哥殑浣撶Н涓篤锛屾墍浠18.4mol/L脳V=0.10mol/L脳1L锛孷=0.0054L=5.4mL锛屾晠绛旀涓猴細5.4锛 锛3锛夊厛鐢ㄩ噺绛掗噺鍙栨祿纭吀锛屾妸娴撶～閰稿掑叆灏忕儳鏉腑杩涜绋閲婏紝鍦ㄧ█閲婅繃绋嬩腑鐢ㄧ幓鐠冩鎼呮媽锛岀瓑婧舵恫鍐峰嵈鍒板娓╁悗杞Щ鍒板閲忕摱涓紝鐢ㄧ幓鐠冩寮曟祦锛屾渶鍚庣敤鑳跺ご婊寸瀹氬锛...
绛旓細瑙ｏ細闇瑕丯aoH鐨勬懇灏旈噺涓0.5L*0.1mol/L=0.05mol 锛屾晠NaoH鐨勮川閲忎负0.05mol*NaoH鐨勭浉瀵硅川閲=0.05mol*40g/mol=2g,鏁呯敤澶╁钩绉板彇2鍏嬶紝
绛旓細搴忓彿娴撳害姘㈡哀鍖栭挔楗卞拰婧舵恫浣撶Н 010.1mol/L5ml 020.2mol/L10ml 030.25mol/L12ml 040.5mol/L26ml 鏍囧畾:0.10mol/L姘㈡哀鍖栭挔鏍囧噯婊村畾婧舵恫绉板彇0.4-0.6鍏;0.20mol/L姘㈡哀鍖栭挔鏍囧噯婊村畾婧舵恫绉1-1.2鍏 0.25mol/L姘㈡哀鍖栭挔鏍囧噯婊村畾婧舵恫绉1.5鍏嬪乏鍙;0.50mol/L姘㈡哀鍖栭挔鏍囧噯婊村畾婧舵恫绉板彇3鍏嬩簬...
绛旓細锛1锛塃 C D B A G F 锛堥『搴忓～閿欎竴涓笉寰楀垎锛夛紙2锛変究浜庤瀵熼敟褰㈢摱鍐呮寚绀哄墏棰滆壊鐨勫彉鍖 锛3锛夆0鈥濆埢搴︽垨鈥0鈥濆埢搴︿互涓嬶紱 鍏呮弧婧舵恫 锛4锛夊亸澶 锛涘亸灏 锛5锛夆憽鈶⑩憼 璇曢鍒嗘瀽锛氾紙1锛夋淮瀹氱鍦ㄤ娇鐢ㄤ箣鍓嶉渶瑕佹煡婕忋佹礂娑ゅ拰娑︽礂锛屾墍浠ユ纭殑鐨勬搷浣滈『搴忔槸 E C D B ...
绛旓細瀹為獙瀹ゆ病鏈800ml鐨勫閲忕摱锛屾湁100ml, 250ml ,500ml ,1000ml杩欏嚑绉嶈鏍硷紝鎵浠ュ簲璇ラ1000ml 鐨勫閲忕摱鏉ラ厤缃婧舵恫锛屾墍浠ユ憾璐ㄥ簲璇ヤ互1000ml婧舵恫涓憾璐ㄦ潵绉伴噺銆傚嵆锛氱～浠ｇ～閰搁挔鏅朵綋鐗╄川鐨勯噺涓猴細1L脳0.10mol/L=0.10mol 纭唬纭吀閽犳櫠浣撶墿璐ㄧ殑璐ㄩ噺涓猴細0.10mol脳248g/mol=24.80g ...
绛旓細鎵闇Na2CO3鐨勬懇灏旇川閲忥細500 ml * 0.1000 mol/l = 0.0500mol Na2CO3鐨勬懇灏旇川閲忥細23 * 2 + 12 + 16 *3锛106 g/mol 鎵浠ュ彇0.0500 mol * 106g/mol = 5.3g
