高一化学题
\u9ad8\u4e00\u5316\u5b66\u9898\u7531\u65e0\u8272\u900f\u660e\u6392\u9664\u4e86\u4e8c\u6c27\u5316\u6c2e\uff0c\u7531\u901a\u8fc7\u6d53\u786b\u9178\u6c14\u4f53\u51cf\u5c11\u63a8\u51fa\u5176\u4e2d\u4e00\u5b9a\u542b\u6c28\u6c14\uff0c\u56e0\u4e3a\u53ea\u6709\u6c28\u6c14\u80fd\u4e0e\u6d53\u786b\u9178\u53cd\u5e94\u800c\u4f7f\u6c14\u4f53\u51cf\u5c11\uff0c\u540c\u65f6\u63a8\u51fa\u539f\u6c14\u4f53\u4e2d\u4e00\u5b9a\u6ca1\u6709\u6c2f\u5316\u6c22\uff0c\u56e0\u4e3a\u6c2f\u5316\u6c22\u4e0e\u6c28\u6c14\u5e38\u6e29\u4e0b\u53ef\u4ee5\u53cd\u5e94\u751f\u6210\u6c2f\u5316\u94f5\u800c\u4e0d\u80fd\u5171\u5b58\uff1b\u901a\u8fc7\u70e7\u78b1\u6c14\u4f53\u4f53\u79ef\u51cf\u5c11\u8bf4\u660e\u542b\u6709\u4e8c\u6c27\u5316\u78b3\uff0c\u6700\u540e\u5269\u4f59\u7684\u6c14\u4f53\u4e0e\u7a7a\u6c14\u63a5\u89e6\u540e\u7acb\u5373\u53d8\u4e3a\u7ea2\u68d5\u8272\u8bf4\u660e\u539f\u6c14\u4f53\u4e2d\u4e00\u5b9a\u6709\u4e00\u6c27\u5316\u6c2e\uff0c\u5219\u4e00\u5b9a\u6ca1\u6709\u6c27\u6c14\u3002
\u7efc\u4e0a\uff0c\u4e00\u5b9a\u6709\u6c28\u6c14\u3001\u4e00\u6c27\u5316\u6c2e\u3001\u4e8c\u6c27\u5316\u78b3\uff1b\u4e00\u5b9a\u4e0d\u542b\u6c2f\u5316\u6c22\u3001\u6c27\u6c14\u3001\u4e8c\u6c27\u5316\u6c2e\uff1b\u53ef\u80fd\u542b\u6c22\u6c14
\u7b54\u6848\uff1aC
\u89e3\u6790\uff1a
A\uff1a\u9519\u8bef\uff0c\u7a00\u785d\u9178\u6709\u5f3a\u6c27\u5316\u6027\uff0c\u4e0d\u4f1a\u548c\u950c\u53cd\u5e94\u751f\u6210H2\uff0c\u91d1\u5c5e\u548c\u785d\u9178\u53cd\u5e94\u4e0d\u4f1a\u6709H2\u751f\u6210\u7684
B\uff1a\u9519\u8bef\uff0c\u5411\u9971\u548c\u98df\u76d0\u6c34\u4e2d\u6ef4\u52a0\u7a00\u786b\u9178\u4e0d\u4f1a\u4ea7\u751fHCl\u7684\uff0c\u53ef\u4ee5\u50cfNaCl\u56fa\u4f53\u4e0a\u6ef4\u52a0\u6d53\u786b\u9178\u6765\u5236\u53d6HCl
C\uff1a\u6b63\u786e
D\uff1a\u5927\u7406\u77f3\u4e0e\u6d53\u786b\u9178\u53cd\u5e94\u751f\u6210\u7684\u786b\u9178\u9499\u4f1a\u8986\u76d6\u5728\u5927\u7406\u77f3\u8868\u9762\uff0c\u963b\u6b62\u53cd\u5e94\u7684\u8fdb\u884c\uff0c\u6240\u4ee5\u4e0d\u80fd\u7528\u6765\u5236\u53d6CO2\uff0c\u7a00\u786b\u9178\u4e5f\u4e0d\u53ef\u4ee5\uff0c\u7406\u7531\u4e00\u6837
(2)设生成40%硝酸的质量为x
N2--------------------2HNO3
28 126
200kg*90%*80%*90% x*40%
解得x=1458kg
（1）N2＋3H2＝高温、高压、催化剂＝2NH3
4NH3＋5O2＝高温、催化剂＝4NO＋6H2O
2NO+O2=2NO2
3NO2+H2O=2HNO3+NO
（2）利用氮元素守恒，则有：
N2－－－－2HNO3
28 126
200kg×90%×80%×90% 40%x
x＝1458 千克
亏你用手机照下来c为ch2或ch3
1.c
c
c
c
c,c,c
,c,c,c
c
c
c
c
2.题目有点问题334是234甲基，34是24乙基
一个碳上面不会有两个甲基的同时有乙基
3.4.如图
<1>N2+3H3--2NH3 4NH3+5O2==4NO+6H2O 2NO+O2=2NO2 NO2+H2O=HNO3
<2>N2~HNO3
200/28=0.4X/0.9*0.8*0.9
1.N2+3H2==2NH3
4NH3+3O2==4NO+6H2O
NO+O2==NO2
3NO2+H2O==2HNO3+NO
绛旓細杩欑棰涓庡瘑搴︽湁鍏炽傚綋瀵嗗害澶т簬1 鏃讹紝绛変綋绉贩鍚堬紝娣峰悎鍚庤川閲忓垎鏁板ぇ浜庤川閲忓垎鏁板拰鐨勪竴鍗婏紱褰撳瘑搴﹀皬浜1 鏃讹紝绛変綋绉贩鍚堬紝娣峰悎鍚庤川閲忓垎鏁板皢灏忎簬璐ㄩ噺鍒嗘暟鍜岀殑涓鍗娿傝繖鍙互閫氳繃璁＄畻寰楀嚭姝ょ粨璁恒3銆佺瓟妗堜负A.姝ら搴旂揣鎶撲綇鐗╄川鐨勯噺娴撳害鐨勬蹇靛垎鏋愩侫涓敱鈶犲拰鈶㈡棤娉曟眰鍑烘憾璐ㄧ殑鐗╄川鐨勯噺銆侭涓敱鈶㈠拰鈶ゅ彲姹傚嚭婧惰川...
绛旓細楂樹竴鍖栧璁＄畻棰,鎬!?? 鎴戞潵绛 1涓洖绛 #楂樼儹# 涓婃捣鎶曟斁寮傜墿鑰呮秹瀚屼粈涔堢姱缃?涔勯毃瑷毃濡冲嫊 2022-06-30 路 TA鑾峰緱瓒呰繃8487涓禐 鐭ラ亾澶ф湁鍙负绛斾富 鍥炵瓟閲:1713 閲囩撼鐜:0% 甯姪鐨勪汉:2987涓 鎴戜篃鍘荤瓟棰樿闂釜浜洪〉 鍏虫敞 灞曞紑鍏ㄩ儴 2Na + 2H2O = 2Na+鍔2OH- 鍔 H2鈫慚g+2H(+)=Mg(2...
绛旓細瑙ｆ瀽锛欰鏄箼閱囷紝CH3CH2OH锛屽湪楂橀敯閰搁捑涓嬶紝鍙互鐢熸垚涔欓吀锛孋H3COOH锛屽湪鍔犵儹鍜屾祿纭吀鐨勪綔鐢ㄤ笅锛孉涓嶼鍙嶅簲鍙敓鎴愪竴绉嶆湁棣欏懗鐨勭墿璐╓锛屽叾瀹炴槸鍙戠敓浜嗛叝鍖栧弽搴旓紝W鏄箼閰镐箼閰侰H3CH2OH+CH3COOH锛嶏紞鍔犵儹锛屾祿纭吀锛嶏紞CH3COOCH2CH3+H2O 46銆60銆88 184g锛堣繃閲忥級120gX 瑙ｅ緱X锛176g 鎵浠ユ敹鐜囦负106/176锛60.22 娉...
绛旓細瑙ｏ細鍙戠敓鍙樺寲鐨勬槸纰抽吀姘㈤挔锛屽浐浣撳噺灏戠殑鏄簩姘у寲纰冲拰姘寸殑璐ㄩ噺 璁惧惈纰抽吀姘㈤挔鍥轰綋x g 2NaHCO3 = Na2CO3 + CO2 + H2O 鍥轰綋鍑忓皯 168 44 18 62 x 10-8.45 鍒楁瘮渚嬫柟绋 x=4.2g 鍘熷浐浣撴贩鍚堢墿涓惈纰抽吀閽10-4.2=5.8g 纰抽吀閽犵殑璐ㄩ噺鍒嗘暟=5.8/10 *100%=58 ...
绛旓細楂樹竴鍖栧鍏稿瀷棰樹緥 1锛庡湪 300 mL 2 mol/L H2SO4 婧舵恫涓紝婧惰川鐨勮川閲忔槸澶氬皯锛熸婧舵恫涓惈 H+ 鐨勭墿璐ㄧ殑閲忔槸澶氬皯锛烪+ 鐨勭墿璐ㄧ殑閲忔祿搴︽槸澶氬皯锛熷叾涓惈鏈夊灏戜釜 SO 锛烻O 鐨勭墿璐ㄧ殑閲忔祿搴︽槸澶氬皯锛 瑙ｏ細58.8 g锛1.2 mol锛4 mol/L锛3.612脳1023锛2 mol/L瑙ｆ瀽锛氭憾璐ㄥ嵆 H2SO4锛宯 (H2SO4...
绛旓細KClO3 +6HCl ==KCl +3Cl2 鈫+3 H2O 杩欐潯鍙嶅簲鏄浆绉讳簡5涓數瀛 KClO3 +6HCl ==KCl +3Cl2 鈫+3 H2O ---5e- 3 5 0.1 x x=0.5/3mol鐢靛瓙 鈶犺嫢浜х敓0.1molCl2锛屽垯杞Щ鐢靛瓙鐨勭墿璐ㄧ殑閲忎负澶氬皯mol? 绛旀0.5/3mol KClO3 +6HCl ==KCl +3Cl2 鈫+3 H2O 浜х墿3Cl2涓6...
绛旓細涓嬮潰鏄垜鏀堕泦鏁寸悊鐨楂樹竴蹇呬慨涓鍖栧鏈熸湯璇曞嵎棰樼洰浠ヤ緵澶у瀛︿範! 楂樹竴蹇呬慨涓鍖栧鏈熸湯璇曞嵎: 绗琁鍗(鍏54鍒) 涓銆侀夋嫨棰(鏈鍖呮嫭12灏忛,姣忛鍙湁涓涓夐」绗﹀悎棰樻剰,姣忓皬棰2鍒,鍏24鍒) 1.瀹归噺鐡朵笂闇鏍囨湁:鈶犳俯搴 鈶℃祿搴 鈶㈠閲 鈶ｅ帇寮 鈶ゅ埢搴︾嚎 鈶ラ吀寮忔垨纰卞紡;鍏」涓殑 ( ) A.鈶犫憿鈶 B.鈶⑩懁鈶 C.鈶...
绛旓細2NaHCO3 = Na2CO3 + CO2 + H2O锛堝姞鐑潯浠讹級锛2NaOH + CO2 = Na2CO3 + H2O銆傛诲弽搴斾负锛歂aHCO3 + NaOH = Na2CO3 + H2O銆傞鍏堣鍒ゆ柇纰抽吀姘㈤挔鍙嶅簲鏀惧嚭鐨凜O2鏄惁鍏ㄩ儴琚阿姘у寲閽犲惛鏀躲100+20-95.5=24.5锛屽亣璁捐繖浜涘叏鏄洜涓烘按閫稿嚭閫犳垚鐨勩侼aHCO3 + NaOH = Na2CO3 + H2O 84 40 106 ...
绛旓細锛1锛2NaOH + H2SO4===2H2O + Na2SO4 NaCO3 + H2SO4===H2O + CO2鈫+ Na2SO4 鍥犱负瀹屽叏鍙嶅簲,鎵浠ュ彲浠ユ牴鎹～閰告牴绂诲瓙鐨勬懇灏旇川閲忔潵璁＄畻纭吀閽犵殑璐ㄩ噺锛岀～閰哥殑鎽╁皵璐ㄩ噺涓98*20%/98=0.2mol 鎵浠ョ～閰搁挔鐨勮川閲忎负0.2*142=28,4g 锛2锛夋牴鎹川閲忓畧鎭掑師鐞嗭紝鐢熸垚鐨勬矇娣鐨勮川閲忓氨鏄弽搴斿墠鐨勬昏川閲忓噺...
绛旓細鍘熷洜锛1.纰抽吀閾朵笉绋冲畾浼氭按瑙ｆ垚姘㈡哀鍖栭摱,鍚屾椂鏀惧嚭CO2 鏂圭▼寮忎负 Ag2CO3+H2O=2Ag(OH)+CO2 2.Na2CO3+AgNO3=Ag2CO3+2NaNO3 鎺ョ潃Ag2CO3+H2O=2Ag(OH)+CO2 锛2锛氬皬鍒氬湪鍖栧瀹為獙瀹ゅ彂鐜帮紝鐩涙斁姘㈡哀鍖栭挔婧舵恫鐨勮瘯鍓傜摱鐡跺彛鍜屾鐨涓婂嚭鐜颁簡鐧借壊绮夋湯銆傚皬鍒氬彨鏉ュ皬鍐涘拰灏忕孩锛屽叡鍚屾帰璁ㄨ繖绉嶇櫧鑹茬矇鏈殑鎴愬垎...
