sin2X-cos2X可以被化简成什么 怎样化简sin2x-cos2x-1=
sin2x+cos2x\u600e\u4e48\u5316\u7b80sin2x+cos2x
= \u221a2\u00b7\u3010cos45\u00b7sin2X + sin45\u00b7cos2X\u3011
= \u221a2\u00b7sin[2X + 45]
\u5bf9\u5427 \u52a0\u6cb9
sin2x=sin(x+x), cos2x=cos(x+x)
\u539f\u5f0f=sinxcosx+sinxcosx-cosx²-sinx²-1
=-(sinx-cosx)²-1
仅供参考
提出一个√2(根号二),变成√2(sin2x-π/4)
绛旓細sin2X-cos2X=鈭2sin2Xcos蟺/4-鈭2cos2Xsin蟺/4=鈭2sin锛2x-蟺/4锛夊彲浠ュ寲绠浜嗭紝鐢变功涓婂叕寮忚繕鍙互鍖栨垚鈭2cos锛2x+蟺/4锛夈傜瓟妗堚垰2sin锛2x-蟺/4锛夋纭垰2cos锛2x+蟺/4锛変篃姝g‘
绛旓細y =sin2x-cos2x =鈭2.sin(2x-蟺/4)
绛旓細sin2X-cos2X =鈭2sin2Xcos蟺/4-鈭2cos2Xsin蟺/4 =鈭2sin锛2x-蟺/4锛夊嶈鍗婅鍏紡锛歴in ( 2伪 ) = 2sin伪 路 cos伪 sin ( 3伪 ) = 3sin伪 - 4sin & sup3 ; ( 伪 ) = 4sin伪 路 sin ( 60 + 伪 ) sin ( 60 - 伪 )sin ( 伪 / 2 ) = 卤 鈭( ( 1 - cos伪...
绛旓細瑙e寲绠鏄牴2sin(x-鍏/4)
绛旓細鎬濊矾锛氬寲涓轰竴涓笁瑙掑嚱鏁帮紝鍏蜂綋濡傦細y= sin2x - cos2x = sin2x - sin(鈭/2-2x) = 2cos[(2x+鈭/2-2x)/2]*sin[(2x-鈭/2+2x)/2] = 2路鈭2/2路sin(4x-鈭/2) = -鈭2路cos4x,鎵浠ュ懆鏈熷氨鏄細T = 2鈭/蠅 = 2鈭/4 = 鈭/2 ....
绛旓細浼间箮涓嶈兘,濡備笅 涓嶈繃涔熷彲浠ュ彉鎴
绛旓細瑙g敱sin2x-cos2x =鈭2锛堚垰2/2sin2x-鈭2/2cos2x锛=鈭2锛坈os蟺/4sin2x-sin蟺/4cos2x锛=鈭2sin锛2x-蟺/4锛夊彧鏈夋彁鍑衡垰2锛屾墠鑳芥瀯閫燾os蟺/4=鈭2/2锛宻in蟺/4=鈭2/2銆
绛旓細2sinxcosx
绛旓細杈呭姪瑙掑叕寮忥紝鎻愬彇绯绘暟骞虫柟鍜屽紑鏍瑰彿锛屼篃灏辨槸浜屽垎涔嬫牴鍙蜂簩
绛旓細sin2x鈥攃os2x =鈭2[sin2xcos(蟺/4)鈥cos2xsin(蟺/4)]=鈭2sin(2x-蟺/4)