设a，b是方程x方+x-2011=0的两个实数根，则a方+2a+b的值为？要步骤
\u8bbea,b\u662f\u65b9\u7a0bx\u7684\u4e8c\u6b21\u65b9\u52a0x-2011\u7684\u4e24\u4e2a\u5b9e\u6570\u6839\uff0ca\u7684\u4e8c\u6b21\u65b9\u52a02a\u52a0b\u7684\u503c\u4e3a\u591a\u5c11\uff1f \u8981\u8fc7\u7a0ba\u3001b\u662f\u65b9\u7a0bx²\uff0bx\uff0d2011=0\u7684\u4e24\u6839\uff0c\u5219a\uff0bb=\uff0d1\uff0ca²\uff0ba\uff0d2011=0\u5373a²\uff0ba=2011\u3002\u5219a²\uff0b2a\uff0bb=(a²\uff0ba)\uff0b(a\uff0bb)=2011\uff0b(\uff0d1)=2010\u3002
\u8bbea,b\u662f\u65b9\u7a0bx\u5e73\u65b9\uff0bx-2011=0\u7684\u4e24\u4e2a\u5b9e\u6570\u6839
\u5219a\u5e73\u65b9+a-2011=0
a\u5e73\u65b9+a=2011
\u6839\u636e\u97e6\u8fbe\u5b9a\u7406\u5f97
a+b=-1
a\u5e73\u65b9+2a+b
=a\u5e73\u65b9+a+a+b
=2011-1
=2010
a²＋a-2011=0
a²=2011-a
a+b=-1
ab=-2011
所以
a²＋2a＋b
=2011-a＋2a＋b
=2011+a+b
=2011-1
=2010
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