知道圆弧的弧长和拱高,怎么求半径 急!知道弧长和拱高怎样求半径,记得写详细点

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\u5047\u8bbe\u5f27\u957fL\u6240\u5939\u89d2\u4e3a\u03b8
\u5219\u6709L=2\u03c0r\u00d7\u03b8/360
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\u6839\u636e\u4f59\u5f26\u5b9a\u7406\uff0ccos(\u03b8/2)=(r-h)/r
\u7ed3\u5408\u4e24\u5f0f,\u03b8=180L/\uff08\u03c0r\uff09\uff0c\u5219\u03b8/2=90L/\uff08\u03c0r\uff09
cos\uff08\u03b8/2\uff09=1-h/r
cos[90L/(\u03c0r)]=1-h/r
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n\u00b0\u7684\u5706\u5fc3\u89d2\u6240\u5bf9\u5f27\u957f\u4e3an\u03c0R/180\u00b0\uff0c\u5e7f\u4e49\u4e0a\u6307\u5149\u6ed1\u66f2\u7ebf\u7684\u5f27\u957f\u3002

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\u62f1\u9ad8\u8ba1\u7b97\u516c\u5f0f\u4e3a\uff1a\u8bbe\u534a\u5f84R\uff0c\u62f1\u5f62\u8ddd\u79bb\u4e3a2a\uff0c\u5219\u62f1\u9ad8h=R-\u221a(R²-a²)\u3002
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\u5219\u6709L=2\u03c0r\u00d7\u03b8/360
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\u6839\u636e\u4f59\u5f26\u5b9a\u7406\uff0ccos(\u03b8/2)=(r-h)/r
\u7ed3\u5408\u4e24\u5f0f\uff0c\u03b8=180L/(\u03c0r)\uff0c\u5219\u03b8/2=90L/(\u03c0r)
cos(\u03b8/2)=1-h/r
cos[90L/(\u03c0r)]=1-h/r
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弧长是C=725毫米,拱高是H=130毫米,半径应该是多少?
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn

R0=505
R1=479.915
R2=482.017
R3=482.034
R4=482.034

R=482.034毫米

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