与椭圆共焦点的双曲线方程怎样设 已知椭圆系方程，与它共焦点的双曲线系如何设
\u6c42\u53cc\u66f2\u7ebf\u4e0e\u692d\u5706\u5171\u7126\u70b9\u65f6\u7684\u65b9\u7a0b\u8bbe\u6cd5\u3002\u4ed6\u4eec\u5171\u7126\u70b9\u7684\u8bdd\u4f60\u5e94\u8be5\u5148\u6c42\u51fa\u7126\u70b9\u5750\u6807\uff0c\u4e5f\u5c31\u662fc\u7684\u503c\uff0c\u7136\u540e\u627e\u5230abc\u7684\u5173\u7cfb\u5f0f\u518d\u8bbe\u53cc\u66f2\u7ebf\u7684\u65b9\u7a0b\uff0c\u8fd9\u6837\u5c31\u53ea\u6709\u4e00\u4e2a\u672a\u77e5\u91cf\uff0c\u7136\u540e\u5e26\u70b9\u6c42\u503c
\u5982\u679c\u692d\u5706\u7684\u7126\u70b9\u5728\u957f\u8f74\uff0c\u540c\u7406 \u53cc\u66f2\u7ebf\u7684\u5b9e\u8f74\u5219\u5728x\u8f74\uff0c\u692d\u5706\u4e0e\u53cc\u66f2\u7ebf\u7684\u79bb\u5fc3\u7387\u4e0d\u53ef\u80fd\u76f8\u7b49\uff0c\u692d\u5706\u7684\u79bb\u5fc3\u7387\u4e3ae=c\a\uff0801\uff09\u4e0e\u692d\u5706\u5173\u6ca1\u6709\u4ea4\u96c6\u3002\u53cc\u66f2\u7ebf\u4e0e\u692d\u5706\u7684\u5173\u7cfb\u6700\u597d\u7ed3\u5408\u56fe\u7247\u770b\uff0c\u6211\u8fd9\u91cc\u8fd8\u6ca1\u6709\u6743\u9650\u8d34\u56fe\u7247\uff0c\u4f60\u53ef\u4ee5\u767e\u5ea6\u4e00\u4e0b\u7ed3\u5408\u7740\u770b\u3002
解：c^2已知设为x^2/a^2-y^2/(c^2-a^2)=1
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