醇醛酸三者是如何转化的？？化学方程式~ 那个醇怎么到醛，醛怎么到酸算怎么到醇。。。（化学式，）在线等
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CH₂=CH₂ + H₂O = CH₃CH₂OH
\u9187\u8f6c\u5316\u4e3a\u919b\uff1a
CH₃CH₂OH + CuO = CH₃CHO + Cu + H₂O
\u919b\u8f6c\u5316\u4e3a\u7fa7\u9178\uff1a
CH₃CHO + 2Cu(OH)₂ = CH₃COOH + Cu₂O + 2H₂O
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\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u9187
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\u9187\u5230\u919b\uff0c\u6c27\u5316\u53cd\u5e94\uff1a
2CH3CH2OH+O2\uff0d(Cu\u6216Ag)/\u25b3\u21922CH3CHO+2H2O
\u919b\u5230\u9178\uff0c\u52a0\u6210\u53cd\u5e94\uff1a
2CH3-CHO+O2\u2014\uff08\u6761\u4ef6\uff1a\u94dc\u6216\u8005\u94f6\u505a\u50ac\u5316\u5242\uff0c\u52a0\u70ed\uff09\u2192 2CH3-COOH
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CH3-CHO + H2 \u2014\uff08\u6761\u4ef6\uff1a\u954d\u505a\u50ac\u5316\u5242\uff0c\u52a0\u70ed\uff09\u2192 CH3-CH2-OH
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醇也可能直接氧化为酮。
醇氧化得醛，醛氧化得酸，也可逆，
醇也可直接氧化成酸
2
ch3-oh
+
o2
----------(cu)--------
2
h2c=o
2
h2c=o
+
o2
-----cu-----
2
hcooh
RCH2OH→RCOH→RCOOH
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绛旓細閱囬啗閰镐箣闂寸殑杞寲鍏崇郴 閱囩殑瀹樿兘鍥㈡槸缇熷熀-OH锛岄啗鏄啗鍩-CHO锛岄吀鏄晶鍩-COOH銆傞唶鍩烘哀鍖栧緱閱涘熀锛岄啗鍩烘哀鍖栫殑缇у熀銆傛哀鍖栬繃绋嬪彲璁や负鏄幓姘㈣繃绋嬨傞唶鐨勫偓鍖栨哀鍖栧弽搴斿彲鐢熸垚閱涳紝渚嬶細鍦ㄩ噾灞為摐鐨勫偓鍖栦綔鐢ㄤ笅锛屼箼閱囧彂鐢熸哀鍖栧弽搴旓細2CH3CH2OH + O2 鈫 2CH3CHO + 2H2O銆傞啗鐨勮繕鍘熷弽搴斿彲鐢熸垚閱囷紝渚嬶細鍦ㄩ晬绮夊仛鍌寲鍓...
绛旓細閱囩殑瀹樿兘鍥㈡槸缇熷熀-OH锛岄啗鏄啗鍩-CHO锛岄吀鏄晶鍩-COOH銆傞唶鍩烘哀鍖栧緱閱涘熀锛岄啗鍩烘哀鍖栫殑缇у熀銆傛哀鍖栬繃绋嬪彲璁や负鏄幓姘㈣繃绋嬶紝閱囩殑鍌寲姘у寲鍙嶅簲鍙敓鎴愰啗锛岄啗鐨勮繕鍘熷弽搴斿彲鐢熸垚閱囷紝閱涚殑姘у寲鍙嶅簲鍗村彲鐢熸垚缇ч吀銆傜敳閰板熀鏄撹杩樺師涓轰集閱(-CH2OH)銆傝繖绉嶅吀鍨嬭浆鍖栦娇鐢ㄤ簡鍌寲姘㈠寲锛屾垨鐩存帴鐨勮浆绉绘阿鍖栬繘琛屻傞啗鍦ㄩ吀鎬х幆澧冧笅琚...
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绛旓細1.閱 閾/閾滃偓鍖栨哀鍖栫敓鎴愰啗锛 鍘绘阿姘у寲鐨勬阿鍦ㄧ纰充笂锛/閰腑闂村惈姘㈢殑纰冲彂鐢熷幓姘㈡哀鍖栵級鍔犲己姘у寲鍓傦紙閰告ч珮閿伴吀閽撅級濡傛灉鏄集閱囷紙杩炵緹鍩虹殑纰充笂杩樻湁涓や釜H锛夊氨鎴愰吀锛屽洜涓哄垵姝ユ哀鍖栦集閱囦細琚哀鍖栦负閱涳紝閱涚殑杩樺師鎬у緢寮猴紝浼氳缁х画姘у寲鎴愮晶閰 浠查唶锛堣繛缇熷熀鐨勭⒊涓婃湁涓涓狧锛変細琚哀鍖栨垚閰紝閰ǔ瀹氾紝涓嶄細鍐嶈...
绛旓細閱鈫閱锛2H(CH2)nOH+O2鈫2H(CH2)n-1CHO+H2O锛閰+閱団啋閰細H(CH2)nCOOH+H(CH2)nOH鈫扝(CH2)nCOO(CH2)nH+H2O锛涢啗鈫掗吀锛2H(CH2)nCHO+O2鈫2H(CH2)nCOOH锛涢吀鈫掗唶锛2H(CH2)nCOOH+H2鈫2H(CH2)n+1OH+H2O锛涢啗鈫掗唶锛2H(CH2)nCHO+H2鈫2H(CH2)n+1OH ...
绛旓細1.2C2H5OH+O2---2CH3CHO+2H2O(Cu鎴朅g鍌寲,鍔犵儹)2.5CH3CHO+2MnO4- +6H+---5CH3COOH+2Mn2+ +3H2O 3.CH3COONa+HCl=CH3COOH+NaCl
绛旓細浠ヤ箼閱囦负渚嬶細2C2H5OH(涔欓唶) + O2==2CH3CHO(涔閱)+2H2O ==> 2CH3CHO(涔欓啗) + O2==2CH3COOH(涔欓吀) (Cu浣滃偓鍖栧墏)杩欎釜鏄珮涓笉瑕佹眰鐨==> CH3COOH(涔欓吀) + 2H2==C2H5OH(涔欓唶)+H2O (AlLiH4(姘㈠寲閾濋攤)浣滃偓鍖栧墏)
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