因式分解要过程
\u51e0\u9053\u56e0\u5f0f\u5206\u89e3\uff0c\u8981\u8fc7\u7a0b1\uff09-x\u7684\u5e73\u65b9+2x+8
=-(x^2-2x-8)
=-(x-4)(x+2)
\uff082\uff09a\u7684\u5e73\u65b9-b\u7684\u5e73\u65b9+2bc-c\u7684\u5e73\u65b9
=a^2-(b^2-2bc+c^2)
=a^2-(b-c)^2
=(a-b+c)(a+b-c)
\uff083\uff09x\u7684\u5e73\u65b9+6xy+8y\u7684\u5e73\u65b9
=(x+2y)(x+4y)
\uff084\uff09m\u7684\u5e73\u65b9+2mn-15n\u7684\u5e73\u65b9
=(m-3n)(m+5n)
(5 )\uff08a-b\uff09\u7684\u5e73\u65b9-\uff08a-b\uff09\u7684\u5e73\u65b9-2
=(a-b-2)(a-b+1)
\uff086\uff09\uff08a+b\uff09\u7684\u5e73\u65b9+\uff08a+b\uff09-6
=(a+b+3)(a+b-2)
\uff087\uff09a\u7684\u5e73\u65b9-2ab+b\u7684\u5e73\u65b9-1
=(a-b)^2-1
=(a-b+1)(a-b-1)
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绛旓細濡傚浘鎵绀
绛旓細瑙ｏ細鍘熷紡 =-4q(p-1)³+2(p-1)²=2(p-1)²[-2q(p-1)+1]=2(p-1)²(-2pq+2q+1)=-2(2pq-2q-1)(p-1)²鍥剧墖鏍煎紡
绛旓細鎮ㄥソ锛佸瘨妯辨殩鏆栦负浣犺В绛旓細鍘熷紡=X^2-6X +8+1 =x^2-6x+9 =(X-3)^2 ^2琛ㄧず骞虫柟 濡傛灉浣犺鍙垜鐨勫洖绛旓紝璇峰強鏃剁偣鍑汇愰噰绾充负婊℃剰鍥炵瓟銆戞寜閽紝锛堟垨鍦ㄥ鎴风鍙充笂瑙掕瘎浠风偣銆愭弧鎰忋戯級浣犵殑閲囩撼锛屾槸鎴戝墠杩涚殑鍔ㄥ姏! 浣犵殑閲囩撼涔熶細缁欎綘甯﹀幓璐㈠瘜鍊肩殑銆傚鏈変笉鏄庣櫧锛屽彲浠ヨ拷闂紝鐩村埌瀹屾垚寮勬噦姝ら!
