用0.10mol/LHCl滴定同浓度CH3NH2溶液,计算化学计量点的PH，若选用甲基橙为指示剂（ 北京理工大学化学类专业怎么样
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终点误差
绛旓細纰辩殑閲忔槸灏戜竴鐐圭殑锛屽洜姝锛瀊锛岄敊璇紱C銆丒鐐瑰搴旂殑鐐规槸鏄鹃吀鎬х殑锛岀粨鍚堢數鑽峰畧鎭掞紝鍏剁瀛愭祿搴︾敱澶у埌灏忕殑椤哄簭涓: c锛圕H 3 COO 锛 锛> c锛圢a 锛 锛> c锛圚 锛 锛> c锛圤H 锛 锛夛紝姝ｇ‘锛汥銆佸浘2瀹為獙閫夌敤鐢插熀姗欎笉鍚堥傦紝鍥犱负鍒氬ソ鍙嶅簲瀹屽叏鏃讹紝婧舵恫鏄剧⒈鎬э紝搴旈夌敤閰氶厼浣滄寚绀哄墏锛岄敊璇
绛旓細鏃犳按纰抽吀閽犲拰鐩愰吀鐨勫弽搴斿紡濡備笅锛歂a2CO3+HCI==2NaCI+CO2+H20 璁綱琛ㄧず鐢ㄥ幓鐩愰吀鐨勪綋绉紙ml)锛孋琛ㄧず鏃犳按纰抽吀閽犵殑娴撳害锛坈om/L锛塵琛ㄧず绉板彇鏃犳按纰抽吀閽犵殑璐ㄩ噺锛堝厠)锛屽垯鏈変笅鍒楀叧绯伙細C*V=m*1000/53.00 (53.00鏄1/2Na2CO3鐨勬懇灏旇川閲忥級璁＄畻鍚庢棤姘寸⒊閰搁挔鐨勭О鏍疯寖鍥存槸锛0.106鈥0.1325锛堝厠锛夊噺閲...
绛旓細缂撳啿婧舵恫涓細pH=pKa + lg c锛圓c-锛/c锛圚Ac锛塴g c锛圓c-锛/c锛圚Ac锛=4.95-4.74=0.21 c锛圓c-锛/c锛圚Ac锛=1.32 闇瑕侀唻閰哥殑浣撶Н锛100/2.23=43.1ml 闇瑕侀唻閰搁挔鐨勪綋绉細100-43.1=56.9ml
绛旓細褰撴憾娑蹭腑NaH2PO4鍜孨a2HPO4鐗╄川鐨勯噺鐩哥瓑鏃讹紝婧舵恫鐨凱H=7.2锛屽彲鏍规嵁涓嬪紡璁＄畻锛2H3PO4+3NaOH=NaH2PO4+Na2HPO4+3H2O 2---3---1---1 0.02---0.03---0.02---0.02 闇瑕0.10mol/L姘㈡哀鍖栭挔婧舵恫鐨勪綋绉负1000*0.03/0.1=300ml.
绛旓細瑙ｏ細闇瑕丯aoH鐨勬懇灏旈噺涓0.5L*0.1mol/L=0.05mol 锛屾晠NaoH鐨勮川閲忎负0.05mol*NaoH鐨勭浉瀵硅川閲=0.05mol*40g/mol=2g,鏁呯敤澶╁钩绉板彇2鍏嬶紝
绛旓細璁＄畻鐢∟aOH娑(0.10mol/l)婊村畾HCOOH(0.10mol/l)鍒板寲瀛﹁閲忕偣鏃舵憾娑茬殑PH,璋㈠暒 甯府蹇欏晩 璇﹁В 鍢垮樋 鎴戞潵绛 1涓洖绛 #鐑# 楣ゅ矖鐖嗙伀鑳屽悗鐨勫師鍥犳槸浠涔?绾卞涓69 2011-10-28 路 TA鑾峰緱瓒呰繃137涓禐 鐭ラ亾绛斾富 鍥炵瓟閲:115 閲囩撼鐜:0% 甯姪鐨勪汉:35.6涓 鎴戜篃鍘荤瓟棰樿闂釜浜洪〉 鍏虫敞 灞曞紑鍏ㄩ儴 ...
绛旓細銆愮瓟妗堛戯細涓や釜銆傜涓涓獊璺冧负HCl琚淮瀹氥丠3PO4琚淮瀹氬埌H2PO4锛涚浜屼釜绐佽穬涓篐3PO4-琚淮瀹氬埌HPO42-锛汬PO42-涓烘瀬寮遍吀婊村畾鏇茬嚎鏃犳槑鏄剧獊璺冦備袱涓傜涓涓獊璺冧负HCl琚淮瀹氥丠3PO4琚淮瀹氬埌H2PO4锛涚浜屼釜绐佽穬涓篐3PO4-琚淮瀹氬埌HPO42-锛汬PO42-涓烘瀬寮遍吀,婊村畾鏇茬嚎鏃犳槑鏄剧獊璺冦
绛旓細1.娴撳害鏄0.1mol/L Ka=c(CH3COO-)*c(H+)/c(CH3COOH)c(CH3COO-)=c(H+)=0.1*1.3%=1.3*10^-3 mol/L 鐢电鐨勯唻閰告瘮杈冨皯锛屽彲浠ュ拷鐣ャ俢(CH3COOH)=0.1mol/L Ka=c(CH3COO-)*c(H+)/c(CH3COOH)=(1.3*10^-3)*(1.3*10^-3)/0.1=1.7*10^-6 2.Ka涓嶅彉锛宲H=4锛宑(H...
绛旓細涓嶈兘 鐩存帴鍑嗙‘婊村畾鍚屾祿搴︾殑HCN
绛旓細纭寲閿板拰纭寲閾滃潎涓嶆憾浜庢按锛屽叾婧朵簬鐩愰吀鏄彂鐢熶簡鍖栧鍙嶅簲锛歁nS+2HCl=MnCl₂+H₂S鈫 CuS+2HCl=CuCl₂+H₂S鈫 涓婅堪涓ゅ紡涓紝纭寲鐗╀笌鐩愰吀鐨勬懇灏旀瘮鍧囦负1:2锛屽嵆锛氭憾瑙0.10鎽╁皵纭寲鐗╅渶瑕0.20鎽╁皵鐩愰吀銆傛墍浠ワ紝鐩愰吀鏈浣庢祿搴︿负锛0.20mol梅1.0L=0.2mol/L 濡傛灉浣犵殑棰樻剰鏄...
