用因式分解法解方程:2x²＋5x-3=0 2x^2+5x-3=0用因式分解法解方程！！！！！！
\u7528\u56e0\u5f0f\u5206\u89e3\u6cd5\u89e3\u65b9\u7a0b\uff1a \uff081\uff09\uff08x-3\uff09²-36=0 (2)5x²+2x=0 (3)3x²-9=0
\uff082x-1)(x+3)=0
2x-1=0 x=1/2
x+3=0
x=-3
(2x-1)(x+3)=0
2x-1=0 x1=1/2
x+3=0 x2=-3
绛旓細2x²-3x=0鍒嗚В涓簒(2x-3)=0 鍥犲紡鍒嗚В娉曡В鏂圭▼锛岄渶瑕佹妸鏈缁堢粨鏋滃啓鎴愬嚑涓洜寮忕浉涔樼殑褰㈠紡 閫氬紡涓 A(X-B)(X-C)(X-D)鈥︹=0锛屼篃灏辨槸璇村彧鑳芥湁涔樻硶 濡傛灉涓涓紡瀛愪竴鏃朵笉鐭ラ亾鎬庝箞鍥犲紡鍒嗚В锛屽彲浠ュ厛鎶婂畠鍐欐垚涓婅堪閫氬紡鐨勬牸寮忥紝鐒跺悗鎶婇氬紡灞曞紑鍜屽師寮忔瘮杈冿紝灏辫兘鍒嗚В鍑哄洜寮忎簡銆
绛旓細锛1锛夛紙2x+3锛夊钩鏂=4锛2x+3锛(2x+3)²-4(2x+3)=0 (2x+3)(2x+3-4)=0 x1=-3/2, x2=1/2 锛2锛2锛坸-3锛=x骞虫柟-9 (x+3)(x-3)-2(x-3)=0 (x-3)(x+3-2)=0 x1=3, x2=-1 锛3锛4x骞虫柟-4x+1=0 (2x-1)²=0 x1=x2=1/2 ...
绛旓細鐢ㄥ洜寮忓垎瑙ｆ硶瑙ｆ柟绋 (2x+1)²=x²(2x+1)²-x²=0 [(2x+1)+x][(2x+1)-x]=0 (3x+1)(x+1)=0 3x+1=0鎴栬厁+1=0 x=-1/3鎴栬厁=-1
绛旓細鍥炵瓟锛鐢ㄥ洜寮忓垎瑙ｆ硶瑙ｆ柟绋: (1)(2x+12)(2x-12)=0 鈭磝1=-6.x2=6 2,(2x-1)鈭2-(3-x)鈭2=0 (2x-1+3-x)(2x-1-3+x)=0 x+2=0鎴3x-4=0 鈭磝1=4/3,x2=-4
绛旓細瑙ｏ細宸﹁竟灞曞紑寰锛2x�0�5-3x+1=3绉婚」寰楋細2x�0�5-3x-2=0鍒嗚В鍥犲紡寰:(x-2)(2x-1)=0鎵浠-2=0鎴2x-1=0鎵浠1=-0.5 x2=2
绛旓細(2x-1)^2=(3-x)^2 (2x-1)^2-(3-x)^2=0 (2x-1+3-x)(2x-1-3+x)=0 (x+2)(3x-4)=0 x1=-2 x2=4/3
绛旓細x=21 杩囩▼濡備笅锛2X+23*4=134 2x=134-92 x=21 鏂圭▼渚濋潬绛夊紡鍚勯儴鍒嗙殑鍏崇郴锛屽拰鍔犲噺涔橀櫎鍚勯儴鍒嗙殑鍏崇郴锛堝姞鏁+鍔犳暟=鍜岋紝鍜-鍏朵腑涓涓姞鏁=鍙︿竴涓姞鏁帮紝宸+鍑忔暟=琚噺鏁帮紝琚噺鏁-鍑忔暟=宸紝琚噺鏁-宸=鍑忔暟锛屽洜鏁懊楀洜鏁=绉紝绉蜂竴涓洜鏁=鍙︿竴涓洜鏁帮紝琚櫎鏁懊烽櫎鏁=鍟嗭紝琚櫎鏁懊峰晢=闄ゆ暟锛屽晢脳闄ゆ暟=琚...
绛旓細(1)鍥犲紡鍒嗚В娉:2x²锛3x锛1锛0 (2x锛1)(x锛1)锛0 鈭磝1锛1/2 x2锛1 (2)閰嶆柟娉:2x²锛3x锛1锛0 2(x²锛3/2 x锛9/16)锛9/8锛1 2(x锛3/4)²锛1/8 鈭磝锛3/4锛澛1/4 鈭 x1锛1/2 x2锛1 ...
绛旓細鍘鏂圭▼锛2X-1)(3X+4)=2X-1绉婚」寰 锛2X-1)(3X+4锛夛紞锛2x锛1锛=0 (2x锛1)(3x锛4锛1)=0 (2x锛1)(3x锛3)=0 (2x锛1)(x锛1)=0 鎵浠2x锛1=0 ,x=1锛2 鎴栬 x锛1=0, x=锕1
绛旓細x^2=2x x^2-2x=0 x(x-2)=0 x=0鎴杧=2
