关于勾股定理的应用题 关于勾股定理的应用题

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23\uff0e\u6c42\u4e0b\u5217\u5404\u5f0f\u4e2dx\u7684\u503c\uff0e
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24\uff0e\u8bbe2+\u7684\u6574\u6570\u90e8\u5206\u548c\u5c0f\u6570\u90e8\u5206\u5206\u522b\u662fx\u3001y\uff0c\u8bd5\u6c42x\u3001y\u7684\u503c\u4e0ex\ufe631\u7684\u7b97\u672f\u5e73\u65b9\u6839\uff0e
25\uff0e\u5c06\u4e00\u4e2a\u4f53\u79ef\u4e3a216cm3\u7684\u6b63\u65b9\u4f53\u5206\u6210\u7b49\u5927\u76848\u4e2a\u5c0f\u6b63\u65b9\u4f53\uff0c\u6c42\u6bcf\u4e2a\u5c0f\u6b63\u65b9\u4f53\u7684\u8868\u9762\u79ef\uff0e
26\uff0e\u5982\u56fe\uff0c\u4e00\u4e2a\u957f\u4e3a5m\u7684\u68af\u5b50\u659c\u9760\u5728\u5899\u4e0a\uff0c\u68af\u5b50\u7684\u5e95\u7aef\u8ddd\u58994m\uff0e
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\uff083\uff09\u82e5\u4f7f\u68af\u5b50\u7684\u9876\u7aef\u8ddd\u5730\u97624.8m\uff0c\u6b64\u65f6\u5e94\u5c06\u68af\u5b50\u518d\u5411\u5899\u63a8\u8fdb\u591a\u5c11\u7c73\uff1f
27\uff0e\u5728\u4e00\u5e73\u76f4\u6cb3\u5cb8l\u7684\u540c\u4fa7\u6709A\uff0cB\u4e24\u4e2a\u6751\u5e84\uff0cA\uff0cB\u5230l\u7684\u8ddd\u79bbAM\uff0cBN\u5206\u522b\u662f3km\uff0c2km\uff0c\u4e14MN\u4e3a3km\uff0e\u73b0\u8ba1\u5212\u5728\u6cb3\u5cb8\u4e0a\u5efa\u4e00\u62bd\u6c34\u7ad9P\uff0c\u7528\u8f93\u6c34\u7ba1\u5411\u4e24\u4e2a\u6751\u5e84A\uff0cB\u4f9b\u6c34\uff0c\u6c42\u6c34\u7ba1\u957f\u5ea6\u6700\u5c11\u4e3a\u591a\u5c11\uff0e\uff08\u7cbe\u786e\u52300.1km)
23\uff0e\u6c42\u4e0b\u5217\u5404\u5f0f\u4e2dx\u7684\u503c\uff0e
\uff081\uff0916x2\ufe6381=0\uff1b
\uff082\uff09\ufe63\uff08x\ufe632\uff093\ufe6364=0\uff0e
\u3010\u8003\u70b9\u3011\u7acb\u65b9\u6839\uff1b\u5e73\u65b9\u6839\uff0e
\u3010\u4e13\u9898\u3011\u8ba1\u7b97\u9898\uff0e
\u3010\u5206\u6790\u3011\uff081\uff09\u65b9\u7a0b\u6574\u7406\u540e\uff0c\u5229\u7528\u5e73\u65b9\u6839\u5b9a\u4e49\u5f00\u65b9\u5373\u53ef\u6c42\u51fax\u7684\u503c\uff1b
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\u5f00\u65b9\u5f97\uff1ax=\u00b1\uff0c
\u89e3\u5f97\uff1ax1=\uff0cx2=\ufe63\uff1b
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\u5219EC===3\uff08m\uff09\uff0e
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AC===4\uff08m\uff09\uff0c
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\u3010\u89e3\u7b54\u3011\u89e3\uff1a\u5982\u56fe\uff0c

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\u2234CN=A\u2032M=3km\uff0cA\u2032C=MN=3km\uff0c
\u2234BC=3+2=5km\uff0c
\u2234AP+BP=A\u2032P+PB=A\u2032B=\u22485.8km\uff0e
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\u662f\u8fd9\u4e2a\u610f\u601d\u5417\uff1f

我看懂题目了,说的是AC与AE重合,明白了,我试着解一下,等等。

当AC与AE重合,所以AD是角平分线。

AC=18,BC=24,这是个3:4:5的直角三角形,所以AB=30

按勾股定理有BD^2=DE^2+BE^2    ,DE=CD=24-BD,BE=30-AE=30-AC

                     BD^2=(24-BD)^2+(30-18)^2

解一元二次方程,可以求得BD长

                 BD=12+ 根号216



没图 解不了 请补充

应该能吧!!11!!

  • 鍕捐偂瀹氱悊鐨勫簲鐢ㄩ鏈夊摢浜?
    绛旓細鍕捐偂瀹氱悊鏄竴涓熀鏈殑鍑犱綍瀹氱悊锛屾寚鐩磋涓夎褰㈢殑涓ゆ潯鐩磋杈圭殑骞虫柟鍜岀瓑浜庢枩杈圭殑骞虫柟銆備腑鍥藉彜浠gО鐩磋涓夎褰负鍕捐偂褰紝骞朵笖鐩磋杈逛腑杈冨皬鑰呬负鍕撅紝鍙︿竴闀跨洿瑙掕竟涓鸿偂锛屾枩杈逛负寮︼紝鎵浠ョО杩欎釜瀹氱悊涓哄嬀鑲″畾鐞嗭紝涔熸湁浜虹О鍟嗛珮瀹氱悊銆傚弬鑰冭祫鏂 璧电埥.涔濈珷绠楁暟.涓浗锛氳档鐖斤紝涓浗鍙や唬 ...
  • 鍕捐偂瀹氱悊搴旂敤棰 鎬
    绛旓細1.宸茬煡绛夎竟涓夎褰㈢殑闈㈢Н涓12.鍒欏畠鐨勮竟闀跨殑骞虫柟鏄斺2.鍦≧T鈻矨BC涓紝鈭燙=90 掳鈭燗=30掳鈻矨BC鐨勫懆闀挎槸2锛屽垯BC=鈥斺3.鏌愭捣宀涗笂鐨勪竴搴ц瀵熺珯浣嶄簬绂绘捣闈350绫冲鐨凞澶勶紝鍦ㄤ竴娆¤瀵熶腑鍙戠幇涓灏忚埞姝e悜娴峰矝鐨勬柟鍚戦┒鏉ャ傚綋灏忚埞鍒拌揪浣嶇疆A鏃舵祴寰椻垹DAC=30 掳锛岀粡杩20绉掑悗锛屽皬鑸瑰埌杈句綅缃瓸锛屽張娴嬪緱鈭燚BC...
  • 姹3閬撲互涓鍕捐偂瀹氱悊鐨勫簲鐢ㄩ,涓嶈澶畝鍗,涔熷埆澶毦,鏈夐鏈夌瓟妗,鏈夊浘鏇...
    绛旓細瑙o細涓ょ偣涔嬮棿锛岀嚎娈垫渶鐭傝殏铓佸綋鐒朵細璧扮洿绾夸簡锛佺硸鍦ㄦ瀛愪腑澶紝閭d箞浠庢瀛愪腑鐐瑰鍋氳竟缂樼殑鍨傜嚎銆傚垎鍒负1.5/2m鍜1/2m锛岃繖涓ゆ潯鏄笁瑙掑舰鐨勭洿瑙掕竟銆傛枩杈逛负瀹冧滑骞虫柟鐨勫拰鍐嶅紑鏂癸紝绛旀涓2鍒嗕箣鏍瑰彿13銆傦紙涓嶅ソ鎰忔濓紝鏈変簺绗﹀彿涓嶄細鎵擄級2..鍦ㄤ竴妫垫爲鐨10m楂樺鏈変袱鍙尨瀛愶紝鍏朵腑涓鍙埇涓嬫爲璧板悜绂绘爲20m鐨勬睜濉橈紝鑰...
  • 鍕捐偂瀹氱悊搴旂敤棰
    绛旓細OC=30脳2=60娴烽噷锛孫B=40脳2=80娴烽噷锛孊C=100娴烽噷銆傗埖OC²+OB²=60²+80²=10000锛孊C²=100²=10000 鈭碠C²+OB²=BC²鈭粹垹BOC=90掳 鈭粹垹BOS=180掳-35掳-90掳=55掳 绛旓細涔欒埞鐨勮埅鍚戞槸鍗楀亸涓55掳銆
  • 鍕捐偂瀹氱悊鐨勫簲鐢ㄩ
    绛旓細鈭碅D鈯C锛孉D=BD=CD锛屸垹EAD=鈭燜AD=鈭燘=鈭燙=45掳 鈭礑E鈯F 鈭粹垹EDF=鈭燗DB=鈭燗DC=90掳 閭d箞鈭燘DE+鈭燗DE=鈭燗DE+鈭燗DF=90掳 鈭燗DE+鈭燗DF=鈭燗DF+鈭燙DF=90掳 鈭粹垹BDE=鈭燗DF锛屸垹ADE=鈭燙DF 鈭碘垹FAD=鈭燘=45掳锛屸垹EAD=鈭燙=45掳 BD=AD锛孋D=AD 鈭粹柍BDE鈮屸柍ADF(ASA)锛屸柍ADE鈮屸柍CDF(...
  • 鏁板 鍕捐偂瀹氱悊搴旂敤棰
    绛旓細锛1锛夎AE涓篨km锛屽垯BE涓(25-X)km AE^2+AD^2=DE^2=CE^2=BE^2+BC^2 瑙e緱X=15锛屽嵆E搴斿缓鍦ㄨ窛A15km澶 锛2锛夊瀭鐩达紝鐞嗙敱濡備笅:鍥犱负AD=BE锛岃A=瑙払锛孉E=BC锛屾墍浠ヤ笁瑙掑舰ADE鍏ㄧ瓑浜庝笁瑙掑舰BEC锛屾墍浠ヨADE=瑙扖 鍥犱负鍦≧t涓夎褰EC涓C+瑙払EC=90搴︼紝鎵浠ヨDEC=180搴-锛堣AED+瑙払EC锛=90...
  • 鏂囪█鏂鍕捐偂瀹氱悊
    绛旓細1. 鏂囪█鏂鍕捐偂瀹氱悊搴旂敤棰锛堥櫎寮曡懎璧村哺锛 鍕捐偂锛氫粖鏈夋睜鏂逛竴涓堬紝钁敓鍏朵腑澶紝鍑烘按涓灏恒傚紩钁荡宀革紝閫備笌宀搁綈銆傞棶姘存繁銆佽懎闀垮悇鍑犱綍锛熺瓟鏇帮細姘存繁涓涓堜簩灏猴紱钁暱涓涓堜笁灏恒傛湳鏇帮細鍗婃睜鏂硅嚜涔橈紝浠ュ嚭姘翠竴灏鸿嚜涔橈紝鍑忎箣锛岄锛屽嶅嚭姘撮櫎涔嬶紝鍗冲緱姘存繁銆傚姞鍑烘按鏁帮紝寰楄懎闀裤傚嬀鑲″畾鐞嗭細鏈変竴涓竴涓堝ぇ灏忕殑...
  • 鍏充簬鍕捐偂瀹氱悊鐨勫簲鐢ㄩ
    绛旓細1.鍒ゆ柇鏈鐭窛绂绘椂浼氫笉浼氬彈褰卞搷灏眔k 鍨傜洿璺濈鏈鐭紝鏈鐭窛绂荤粡璁$畻涓120km锛屾槸25km鐨4.8鍊嶏紝椋庡姏鍦7-8绾т箣闂达紝鍥犳浼氬彈褰卞搷.2.绂诲彴椋庝腑蹇8脳25=200km鍙笉鍙楀奖鍝 绠楃殑鍙伴浜х敓褰卞搷鐨勮矾绋嬩负 160脳2=320 褰卞搷鏃堕棿320/20=16灏忔椂.3銆佸弬鐓1鐨勬柟娉曞彲寰楅閫熶负7.2绾 ...
  • 鍏充簬鍕捐偂瀹氱悊搴旂敤棰
    绛旓細1 璁剧鍦伴潰x绫冲鎶樻柇 x^2 + 9.6^2 =锛12.8-x锛塣2 锛坁2鍗 骞虫柟锛夊緱 x = 2.8 鈭 浠庡湴闈2.8绫冲鎶樻柇 2 鍘熷紡= a/鏍瑰彿a(鏍瑰彿a-鏍瑰彿b锛 - 鏍瑰彿b/(鏍瑰彿a-鏍瑰彿b锛= 鏍瑰彿a/(鏍瑰彿a-鏍瑰彿b锛 - 鏍瑰彿b/(鏍瑰彿a-鏍瑰彿b)= (鏍瑰彿a-鏍瑰彿b)/(鏍瑰彿a-鏍瑰彿b锛= 1 ...
  • 鍕捐偂瀹氱悊瑙g瓟棰20閬撻檮杩囩▼绛旀,涓瀹氭槸搴旂敤棰,涓嶈濉┖閫夋嫨涔嬬被銆俖鐧 ...
    绛旓細锛1锛(3x+1)^2=7 瑙o細(3x+1)^2=7 鈭(3x+1)^2=7 鈭3x+1=卤鈭7(娉ㄦ剰涓嶈涓㈣В) 鈭磝= (卤鈭7-1)/3 锛2锛9x^2-24x+16=11 瑙o細 9x^2-24x+16=11 鈭(3x-4)^2=11 鈭3x-4=卤鈭11 鈭磝= (卤鈭11+4)/3 鈭村師鏂圭▼鐨勮В涓簒1=(鈭11+4)/3 x2=(-鈭11+4)/3 (3) ...
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