韩信点兵奥数题怎么解？ 关于韩信点兵与孙子问题的那一道题怎么解
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努力算算吧,答案是
=261
设n=5k+3=4p+1=7q+2
首先考虑
5k+3=4p+1
所以k=4（p-k）-2=4（p-k-1)+2=4t+2
所以p=（5k+2）/4=5t+3
n=5k+3=20t+13
再考虑20t+13=7q+2
所以t=21t-7q+11=7（3t-q+1）+4=7s+4
所以n=20t+13=20*(7s+4)+13=140s+93
最小自然数是93
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