数列极限的唯一性证明 极限的唯一性证明
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用定义二，任给一个大于零的数§，在(a；§)的邻域之外数列an中的项只有有限个。则数列an收敛于极限a。证明数列极限的唯一性。对任意一个不等于a的数
采用反证法。先假设数列存在两个不相等的极限a,b且a>b
然后根据极限的定义，取ε=(a-b)/2
很容易可以推出矛盾。
希望我的回答对你有帮助。
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