谁能给在下举一个反对称矩阵的例子?
\u6025\uff01\uff01\uff01\uff01\uff01\uff01\uff01\u8bc1\u660e\u4efb\u610f\u4e00\u4e2an\u9636\u65b9\u9635\u53ef\u4ee5\u8868\u793a\u6210\u4e00\u4e2a\u5bf9\u79f0\u77e9\u9635\u548c\u53cd\u5bf9\u79f0\u77e9\u9635\u4e4b\u548c\u4efb\u610f\u4e00\u4e2an\u9636\u65b9\u9635A\u90fd\u53ef\u4ee5\u8868\u793a\u4e3a\u4e00\u4e2an\u9636\u5bf9\u79f0\u77e9\u9635\u4e0e\u4e00\u4e2an\u9636\u53cd\u5bf9\u79f0\u77e9\u9635\u4e4b\u548c\u662f\u6b63\u786e\u7684\u3002
AT\u8868\u793aA\u7684\u8f6c\u7f6e\u77e9\u9635\uff1a
\u4ee41=\uff08A+AT\uff09/2\uff0cC=\uff08A-AT\uff09/2\uff0c\u5219\uff1a
A=1+C\u3002
\u5176\u4e2d1\u662f\u5bf9\u79f0\u77e9\u9635\uff081T=1\uff09\u3002
\u4e3b\u8981\u4f18\u52bf\uff1a
\u5728\u6570\u5b66\u4e2d\uff0c\u77e9\u9635\u662f\u4e00\u4e2a\u6309\u7167\u957f\u65b9\u9635\u5217\u6392\u5217\u7684\u590d\u6570\u6216\u5b9e\u6570\u96c6\u5408\u3002\u6700\u65e9\u6765\u81ea\u4e8e\u65b9\u7a0b\u7ec4\u7684\u7cfb\u6570\u53ca\u5e38\u6570\u6240\u6784\u6210\u7684\u65b9\u9635\u3002\u8fd9\u4e00\u6982\u5ff5\u753119\u4e16\u7eaa\u82f1\u56fd\u6570\u5b66\u5bb6\u51ef\u5229\u9996\u5148\u63d0\u51fa\u3002
\u4f5c\u4e3a\u89e3\u51b3\u7ebf\u6027\u65b9\u7a0b\u7684\u5de5\u5177\uff0c\u77e9\u9635\u4e5f\u6709\u4e0d\u77ed\u7684\u5386\u53f2\u3002\u6210\u4e66\u6700\u8fdf\u5728\u4e1c\u6c49\u524d\u671f\u7684\u300a\u4e5d\u7ae0\u7b97\u672f\u300b\u4e2d\uff0c\u7528\u5206\u79bb\u7cfb\u6570\u6cd5\u8868\u793a\u7ebf\u6027\u65b9\u7a0b\u7ec4\uff0c\u5f97\u5230\u4e86\u5176\u589e\u5e7f\u77e9\u9635\u3002
\u8bc1\u660e\uff1a
\u4e3a\u4fbf\u4e8e\u4e66\u5199\uff0c\u7528A'\u8868\u793aA\u7684\u8f6c\u7f6e\u77e9\u9635\uff1a
\u4ee4B = (A+A')/2\uff0cC = (A-A')/2\uff0c\u5219
A = B + C
\u5176\u4e2dB\u662f\u5bf9\u79f0\u77e9\u9635(B'=B)
C\u662f\u53cd\u5bf9\u79f0\u77e9\u9635(C'=-C)
\u8bc1\u6bd5
A=(aij)是反对称矩阵，那么有aij=-aji，当i=j时当然就有aii=-aii，那么aii=0
满足这个条件就是反对称矩阵
如方阵第一行为12，6，1第二行-6，8，0第三行-1，0，6 （符号不好画，纯手打）
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